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Airida [17]
3 years ago
7

Consider a snooker ball, with a mass of 0.07kg, rolling along a table at a speed of 4.1m/s. It hits a side cushion of the snooke

r table in a head-on elastic collision.
If the ball and cushion are in contact for 72 milliseconds, what is the size of the net force applied to the ball during this collision, in newtons?
Physics
1 answer:
zavuch27 [327]3 years ago
4 0

Answer: - 3.4 \times 10^{-3} N

Explanation:

From Newton's law of motion, Force is equal to rate of change of momentum.

The initial velocity of the ball, u = 4.1 m/s

mass of the ball, m = 0.07 kg

During contact, velocity = 0

Time of contact, t = 72 ms = 72 × 10⁻³ s

F = \frac{m(v-u)}{t} = \frac{0.07 kg \times (0-4.1 m/s)}{72 \times 10^{-3}s} = - 3.4 \times10^{-3} N

Thus, net force applied to the ball during this collision is - 3.4 \times 10^{-3} N

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According to Coulomb’s Law, the force between two charged objects is related to _____.
Natasha_Volkova [10]

Answer:

A.) the inverse of the square of the distance separating them

Explanation:

Coulombs law states that "the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them."

Mathematically, F = kq1q2/r²

Where q1 and q2 are the charges

r is the distance between the charges.

According to the law, the force between two charged objects is related to the inverse of the square of the distance separating them.

5 0
3 years ago
Why do most scientists follow a set order of steps when carrying out a scientific investigation?
eimsori [14]
<span>Scientists follow a set order of steps when carrying out a scientific investigation to make sure that the method, interpretation and results that they have obtained are repeatable and reliable. This kind of information can be truly said that their data is true and valid. </span>
6 0
3 years ago
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What is the logical relationship between the following two categorical propositions? Some food is not edible. Some food is inedi
sveta [45]
The answer is A. Contrapositive
3 0
3 years ago
How much work does it take to move a 50 μC charge<br> against a 12 V potential difference?
lukranit [14]
<span>work =V*Q =12*50*10^-6

The total work done will be equal to 

work = V.Q

which means 

w= 12 . 50.10^-6
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w= 0.0006 J</span>
8 0
3 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
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