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SpyIntel [72]
3 years ago
9

Identify the following neutral elements by their condensed electron configurations. (Enter the chemical symbol or name of the el

ement.)
(i) [Kr] 5s1 4d10


(ii) [Xe] 6s2 4f14 5d7


(iii) [Ar] 4s2 3d10 4p4


(iv) [Kr] 5s1 4d4


(v) [Xe] 6s1 4f14 5d10


(vi) [Kr] 5s2 4d10 5p4


(b) Based on the electron configurations in part (a), which of the identified elements will have similar properties? Explain. (Enter the chemical symbols of the elements. Separate substances in a list with a comma.)

Elements with similar electron configurations, regardless of which shell each subshell is in, will likely have similar properties.

There are two atoms with the same number of electrons in the outermost d subshell.
Chemistry
1 answer:
Xelga [282]3 years ago
5 0

Answer: [Kr] 5s1 4d10 silver

[Xe] 6s2 4f14 5d7 Iridium

[Ar] 4s2 3d10 4p4 selenium

[Kr] 5s1 4d4 niobium

[Xe] 6s1 4f14 5d10 gold

[Kr] 5s2 4d10 5p4 tellurium

Explanation:

Selenium and tellurium will have the same properties because they both belong to group 16 in the periodic table.

Silver and gold will have the same properties because they both belong the group 11 in the periodic table.

Elements having the same outermost shell configuration show similar properties since chemical reactions occur by loss or gain of electrons. This loss or gain is determined by the number of electrons occupying the outermost shell. Elements in the same group have the same outermost shell electron configuration and similar properties.

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Question 4 (1 point)
Diano4ka-milaya [45]

In an endothermic reaction products are <u>HIGHER </u>than reactants in potential energy and <u>LESS </u>stable.

Explanation:

Energy is input into the reaction in an endothermic reaction. This means the products are of a higher energy level than the reactants. Therefore the reaction increases Gibb's free energy and reduces entropy. Remember in thermodynamic stability involves an increase in entropy and a decrease in Gibbs free energy. Therefore the products are less stable than the reactants. This is why endothermic reactions do not occur spontaneously like exothermic reactions.

6 0
2 years ago
Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
Write out a balanced, molecular equation, total ionic equation, and net ionic equation for each:
dangina [55]

Answer:

1:MgCO3 (s) + 2 NaNO3

2:agcl(s)+kno3(aq)

3:alcl3(aq)+h2(g)

4:NaNO3 + CO2 + H2O

(not sure abt last one)

6 0
3 years ago
Which of the following shows how rate depends on concentrations of reactants?
Katarina [22]

Answer:

Rate = k(A)m(B)n

Explanation:

A.P.E.X.

6 0
3 years ago
What is wind?
barxatty [35]

Answer:

air that moves from high pressure to low pressure

5 0
2 years ago
Read 2 more answers
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