4 years ago

Are wind-driven currents found near the surface of the oceans or in the deep waters of the ocean?

Physics

1 answer:

drek231 [11]4 years ago

5 0

Wind-driven currents are found NEAR THE SURFACE of the oceans

Explanation:

Surface currents are at the interphase between the hydrosphere and atmosphere. Therefore the feel the greatest effect of drag by wind currents, especially prevailing winds (that blow predominantly in one direction like westerlies and easterlies) within the lower atmosphere. The deep currents, on the other hand, are more influenced by Coriolis effect of the earth’s rotation. It is these differences in influences of surface and deeper currents that cause Ekman transport in oceans.

Learn More:

For more on surface and deep ocean currents check out;

brainly.com/question/3552427

brainly.com/question/3008799

brainly.com/question/3700721

brainly.com/question/11975138

brainly.com/question/2804873

#LearnWithBrainly

You might be interested in

An airplane accelerates from a speed of 88m/s to a speed of 132 m/s during a 15 second time interval. How far did the airplane t

Gelneren [198K]

Answer:

$1650\:\mathrm{m}$

Explanation:

We can use the following kinematics equations to solve this problem:

$v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x$ .

Using the first one to solve for acceleration:

$132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}$ .

Now we can use the second equation to solve for the distance travelled by the airplane:

$132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}$ (three significant figures).

6 0

3 years ago

1. Una pelota rueda hacia la derecha siguiendo una trayectoria en línea recta de modo que recorre una distancia de 10m en 5 s ,

devlian [24]

Answer:

https://youtu.be/ymHHdoCGJOU

8 0

3 years ago

Particles of charge +75, +48, and -85μC are placed in a line. The center one is 0.35 m from each of the others. Calculate the ne

ikadub [295]

+X axis is passing through from +75 to +48. then to _83
Now force on +75 due to +48 is being repulsive, with the direction -X, So the X component of force is negative.
Force on +75 due to -85 is attractive, with the direction of +X.
∴ The X component of force is positive
K is always constant and positive.

4 0

4 years ago

As a rocket rises, its kinetic energy changes. At the time the rocket reaches its highest point, most of the kinetic energy of r

Ulleksa [173]

<span>D transformed into gravitational potential energy.</span>

7 0

3 years ago

Read 2 more answers

When electrons are accelerated by 2450 V in an electron microscope, they will have

Anni [7]

I think the answer to this is 0.811nm

5 0

3 years ago