Answer:
I think the answer is Nonmetal...
Answer:
Explanation:
Saturn orbital period
p(s)= 29.46years
Average distance
a(s) = 9.54AU
Venus orbital period
p(v) = 0.62 years
a(v) ?
Using Kepler's third law
a³ ∝p²
a³ = kp²
a³/p² = k
Where
a is the distance if planet from sun
T is the period of the planet
Then,
a(Venus)³/p(venus)² = a(saturn)³/p(saturn)²
a(v)³/p(v)² = a(s)³/p(s)²
a(v) ³/ 0.62² = 9.54³/29.46²
a(v) ³/ 0.62² = 1.0004
a(v)³ = 1.0004× 0.62²
a(v)³ = 0.3846
a(v) = cube root(0.3846)
a(v) = 0.727 AU
11 is the answer for this question
The reactance of an inductor is given by:
X = 2πfL
X is the inductor's reactance
f is the frequency of the supplied voltage
L is the inductor's inductance
The given values are:
f = 60.0Hz
L = 43.8mH (I'm assuming the value is given in milli Henries because this is within the normal range of inductors)
Plug these values in and solve for X:
X = 2π(60.0)(43.8×10⁻³)
X = 16.512Ω
Round this value to 3 significant figures:
X = 16.5Ω
The relationship between AC voltage and current is given by:
V = IZ
V is the voltage
I is the current
Z is the impedance
For an AC inductor circuit, Z = X = 16.512Ω and V is the rms voltage 120V. Plug these values in to get the rms current:
120 = I×16.512
I = 7.2673A
Round this value to 3 significant figures:
I = 7.27A