Answer:
A
Explanation:
In a galvanic cell, energy is produced by spontaneous chemical processes.
The cathode and anode of this cell will depend on the relative position of the two metals in the electrochemical series.
Aluminium is higher in the electrochemical series so aluminium will be the anode. Silver is lower in the electrochemical series so silver will be the cathode.
Recall that oxidation (electron loss) occurs at the anode while reduction (electron gain) occurs at the cathode.
Answer:
Specific heat of metal of the metal is 0.8394J/g°C
Explanation:
The heat the water gain is the same losing for the metal. The equation is:
m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)
<em>Where m is mass: 66.0g water and 28.5g Metal</em>
<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>
<em>And S is specific heat of water (4.184J/g°C) and the metal</em>
<em />
Replacing:
28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C
S(Metal) = 0.8394J/g°C
<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>
<em />
Answer:We will use an acid to test whether sample contains calcium carbonate or not.
Explanation:
Calcium carbonate reacts with acids to give off carbon-dioxide gas ,water and calcium chloride. it is a salt of strong base calcium hydroxide and weak acid carbonic acid.
Evolution of carbon-dioxide on the reaction is also termed as effervescence.
If the sample contains the calcium carbonate strong effervesces will be observed and if not no effervescence will be observed.
We will use an acid to test whether sample contains calcium carbonate or not.
NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)<br>
3,1,1,3<br>
1,2,3,1<br>
3,1,3,1<br>
1,1,3,3
BaLLatris [955]
Answer:
A 3,1,1,3
Explanation:
hope the picture help u to understand :)
For every 2 moles of Li3N, you need 1 mole of N2
so for 0.08 mol Li3N, you need 0.04 moles N2
