<h3>
Answer:</h3>
126.14 g
<h3>
Explanation:</h3>
- Complete combustion of hydrocarbons yields water and carbon dioxide.
- Methane is a hydrocarbon in the homologous series known as alkanes.
- Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.
CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
<u>We are given;</u>
We are required to determine the mass of H₂O produced
<h3>Step 1: Moles of H₂O produced</h3>
- From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.
Therefore, Moles of methane = Moles of H₂O × 2
Hence, Moles of H₂O = 7.0 moles
<h3>Step 2: Mass of H₂O produced </h3>
We know that; mass = Moles × Molar mass
Molar mass of water = 18.02 g/mol
Therefore;
Mass of water = 7.0 moles × 18.02 g/mol
= 126.14 g
Thus, the mass of water produced is 126.14 g
Answer is: 1.23 moles of diphosphorus pentoxide.
1.23mol O2x 1molP2O5= 1.23 moles of diphosphorus pentoxide.
Answer:
Given, Mass of an object, m = 2kg
velocity, v = 2m/s
We have,
KE = 1/2 m v²
= 1/2 × 2 (2)²
= 1/2 × 8
= 4J
Hence, 4J is the required Kinetic energy.
Answer:
Stronger!
Explanation:
The <u>stronger</u> the forces among the particles in a sample of matter, the more rigid the matter will be.
Answer:Consider a sample that is a mixture composed of biphenyl, benzoic acid, and benzyl alcohol. The sample is spotted on a TLC ... Predict the relative Rf values for the three components in the sample. Hint: See Table 19.3. ... The sample is spotted on a TLC plate and developed in solvent mixture. We are going to predict the ...
Explanation:MORE POWER
