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3 years ago

How does electrolysis work

2 answers:

8 0

Electrolysis process be which electric current is passed through a substance to effect a chemical change . Also process is carried out in an electrolytic cell an apparatus consisting of positive and negative electrodes held apart and dipped into a solution containing positively and negatively changed ions.

liberstina [14]3 years ago

5 0

Eeletrolysis is a method of removing individual hairs from the face or body .Medical electrolysis devices destroy the growth center of the hair with chemical or heat energy.After a very fine probe is inserted into the hair follicle, the hair is removed with tweezers

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Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of

dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Na₂CO₃: 1 mole
HCl: 2 moles
NaCl: 2 moles
CO₂: 1 mole
H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

$amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}$

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

$amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}$

amount of moles of NaCl= 0.0554 moles

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

8 0

3 years ago

Find the mass of an object on earth if its weight is 100N

Kaylis [27]

Answer:

0.19 kg

8 N

1.964 N

58.86 N

15 kg

Explanation:

w = Weight of an object = 100 N

g = Acceleration due to gravity of Earth = $9.81\ \text{m/s}^2$

m = Mass of an object

Weight is given by

$w=mg\\\Rightarrow m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{100}{9.81}\\\Rightarrow m=10.19\ \text{kg}$

Mass of the object is 0.19 kg

g = $2\ \text{m/s}^2$

m = 4 kg

$w=mg\\\Rightarrow w=4\times 2\\\Rightarrow w=8\ \text{N}$

Weight of the object is 8 N.

m = 200 g

$w=mg\\\Rightarrow w=0.2\times 9.81\\\Rightarrow w=1.964\ \text{N}$

Weight of the object is 1.964 N.

Weight is the force the Earth exerts on an object which is on the surface of the Earth.

m = 6kg

$w=mg\\\Rightarrow w=6\times 9.81\\\Rightarrow w=58.86\ \text{N}$

The force of the object is 58.86 N.

w = 150 N

a = g = $10\ \text{m/s}^2$

$m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{150}{10}\\\Rightarrow m=15\ \text{kg}$

Mass of the object is 15 kg.

7 0

3 years ago

1.25 moles of NOCl were placed in a 2.50 L reaction chamber at 427ºC. After equilibrium was reached, 1.10 moles of NOCl remained

kenny6666 [7]

Answer:

5.6 × 10^4

this is ur answer hope it helps u

5 0

3 years ago

a mixture of carbon and sulfur has a mass of 9.0 g. complete combustion with excess o2 gives 22.5 g of a mixture of co2 and so2.

photoshop1234 [79]

S + O2 → SO2
z / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x (64.0638 g SO2/mol) = (1.9979 z) g SO2 

C + O2 → CO2 
(9.0-z) / (12.01078 g C/mol) x (1 mol CO2 / 1 mol C) x (44.00964 g CO2/mol) = (32.9776 - 3.66418 z) g CO2 

Add the two masses of SO2 and CO2 and set them equal to the amount given in the problem: 
(1.9979 z) + (32.9776 - 3.66418 z) = 27.9 
Solve for z algebraically: 
z = 3.0 g S

7 0

3 years ago

The mass spectrum of an unknown compound has a molecular ion peak with a relative intensity of 57.10% and an M+1 peak of 6.83%.

max2010maxim [7]

There are 11 Carbon atoms in the compound.

Solution:

Carbon atom count is the ratio of the M peak to the M+1 peak.

$\text{ Number of Carbon atoms }=\frac{\text { Relative intensity of } M+1 \text { peak }}{0.011 \times \text { Relative tntensity of } M \text { peak }}$

Here M peak is 57.10% and M+1 peak is 6.83%. On applying the values in the formula we get,

$\frac{0.0683}{0.011\times0.571g} = 10.87\approx11$

Therefore, the number of Carbon atoms in the compound are 11.

Refer the image attached below for a better understanding of M peak and M+1 peak.

The heaviest ion that has the greatest m/z value is said to be the molecular ion peak in mass spectrum.

6 0

3 years ago