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stepladder [879]
3 years ago
10

How many grams are 1.42 x 10^26 ammonia molecules?

Chemistry
1 answer:
WITCHER [35]3 years ago
6 0

Answer:

4,017.279 grams

Explanation:

Step 1:

Write the formula of calculating no of particles

No of Particles = moles * Avogadro's No ----------(1)

As

moles = grams of molecules / Molecular Mass --------(2)

Step 2:

Put equation(2) moles value in equation (1)

No of Particles = (grams of molecules / Molecular Mass)* Avogadro's No

Molecular Mass of Ammonia = 17.031 g/mol

eq(1) -----> 1.42 x 10^26 = (grams of Ammonia / 17.031) *6.02 x 10^23

solving for gram of ammonia = 4,017.279 grams

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