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Aleonysh [2.5K]
3 years ago
7

A car starts from rest and accelerated at a rate of 9m/s squared for 6.5 seconds. How much distance was covered by the car?

Physics
1 answer:
ki77a [65]3 years ago
5 0

Answer:

58.5 meters

Explanation:

1. Find your formula. Use distance = speed x time for this problem

2. Plug in the given information. d (for distance) = 9m/s^2 * 6.5 s

3. Multiply number AND units. d = 58.5m

4. Check to make sure units & numbers make sense. In this case check that the answer is a lot bigger than what we stated with and that our units go with distance

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A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.9m/s and the hatchback ca
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Answer:

s = 589.3 m

Explanation:

Let the truck and car meet at a distance = s  m

The truck is moving at constant velocity = v

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car:

Vi = 0 m/s

a = 3.9 m/s²

s = Vi* t + 1/2 a t²

s= 0 * t +  1/2 a t²

s =  1/2 a t²   ----------- (2)

compare equation (1)  and equation (2)

s= v * t = 1/2 a t²

⇒ v * t = 1/2 a t²

⇒ t = 2 * v/ a

⇒ t = (2 * 33.9 )/ 3.9

⇒ t = 17. 38 s

Now

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s= v * t

s= 33.9 * 17.38

⇒ s = 589.3 m

3 0
3 years ago
A falcon can descend with a speed 250 km/h. If a falcon flies at this speed for 2.0 s and then flies a 100 m in 2.5 s, what is t
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Answer:

v= s/t

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Average speed:

v=139m+100m/2s+2.5s = 239/4.5s = 53.2 m/s=192km/h

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Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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