Question

The current in a coil with a self inductance of 1.5 mH increases from 0 to 1.0 A in a tenth of a second. What is the induced emf in the coil

Answer 1

Answer:

the induced emf in the coil is 15 mV.

Explanation:

Given;

self inductance, L = 1.5 mH = 1.5 x 10⁻³ H

change in current = dI = 1.0 A

change in time, dt = 1/10 = 0.1

The induced emf is calculated as;

$Induced \ EMF = L (\frac{dI}{dt} )\\\\Induced \ EMF = 1.5 \times 10^{-3}\ (\frac{1}{0.1} )\\\\Induced \ EMF = 1.5 \times 10^{-3} \ \times \ 10\\\\Induced \ EMF = 15 \times 10^{-3} \ V\\\\Induced \ EMF = 15 \ mV$

Therefore, the induced emf in the coil is 15 mV.