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aliya0001 [1]
2 years ago
15

Speed is determined based on two factors. What are they

Physics
1 answer:
a_sh-v [17]2 years ago
7 0

Answer:

distance and time

Explanation: the farther you go and how much time it will take you

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A force of 200 N stretches a spring 30 cm. What is the spring constant of the spring? How far would this spring stretch with a f
bija089 [108]

Hooke's Law

F = k. Δx

Δx = 30 cm = 0.3 m

200 = k . 0.3

\tt k =\dfrac{200}{0.3}= 666.6

the spring stretch for 100 N:

\tt \Delta x=\dfrac{100}{666.6}=0.15=15\:cm

4 0
2 years ago
Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?
CaHeK987 [17]
In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.
7 0
3 years ago
Read 2 more answers
A rifle that shoots bullets at 477 m/s is to be aimed at a target 45.5 m away. If the center of the target is level with the rif
Free_Kalibri [48]

Answer:

The rifle barrel must be pointed at a height of 4.45cm above the target so that the bullet hits dead center.

Explanation:

First, we need to sketch the situation so we can have a better idea of what the problem looks like (Refer to uploaded picture).

So as you may see in the drawing, when pointing the rifle to the target, we can see it as a triangle, but in reality, the bullet will have a parabolic trajectory. Both points of view will help us determine what the height must be. In order to find it, we need to first determine at what angle the bullet should be shot. In order to do so we can use the range formula, which looks like this:

R=\frac{v^{2}sin(2\theta)}{g}

Where R is the range of the bullet (this is how far it goes before it has the

same height it was shot from), v is the original speed of the bullet, θ is the angle at which the bullet is shot and g is the acceleration of gravity.

We can solve this equation for theta, so we get:

gR=v^{2}sin(2\theta)

\frac{gR}{v^{2}}=sin(2\theta)

sin^{-1}(\frac{gR}{v^{2}})=2\theta

\theta=\frac{sin^{-1}(\frac{gR}{v^{2}})}{2}

so now we can substitute the given data:

\theta=\frac{sin^{-1}(\frac{(9.8m/s^{2})(45.5m)}{(477m/s)^{2}})}{2}

so we get:

θ=0.05614°

once we get the angle, we can look at the triangle diagram. From the drawing we can see that we can use the tan function to find the height:

tan \theta = \frac{h}{45.5m}

so we can solve this for h, so we get:

h=45.5m*tan(0.05614^{o})

which yields:

h=0.0445m

or

h=4.45cm

5 0
2 years ago
Help pls it’s urgent giving brainiest!!
Lorico [155]

Answer:

2nd no. positive.... 3rd no. negitive......

3 0
2 years ago
A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces potential energy U(x) given by U(
noname [10]

Answer:

Explanation:

U(x)=αx⁴

Force F = - dU / dx

= 4αx³

= 4 x .75 x³

= 3 x³

Force when x = .8 m

F =  3 (0.8)³

= 1.54 N

8 0
3 years ago
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