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marta [7]
3 years ago
14

Multiple-Choice Homework Problem 3.1 [3 pt(s) ] A negatively charged particle is fixed at the origin. What is the direction of t

he electric field at a point along the positive x axis
Physics
1 answer:
faltersainse [42]3 years ago
5 0

Answer:

Towards the origin on the positive x-axis.

Explanation:

  • For a negatively charged particle the direction electric field lines is always into the charge. So, when a negative charge is placed on the origin then the direction of the electric field lines will be 180° to the positive x-axis, i.e. the field lines will be travelling from infinity towards the origin.
  • Contrary to this the positive charges have the direction of electric field lines emerging out from the charge.
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Electromagnetic waves do not require a medium to travel through. They can travel through empty space or matter.
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Chinook salmon are able to move upstream faster by jumping out of the water periodically; this behavior is called porpoising. Su
deff fn [24]

Answer:he formula for average speed is (total distance/total time)

the y-component does not matter in this problem. so do 6.26(cos45)=4.43m/s to find the x-component velocity which is constant throughout the duration of the flight. the total distance is 2L because he travels distance L twice.

the total time is ((time in water)+(time out of water)) since you dont have time you must eliminate it. to do this you need (distance)/(time)=velocity

solve for time and you get T=D/V

time in water is L/3.52 and time out of water is L/4.43

add them together and you get (4.43L+3.52L)/(15.59) = 7.95L/15.59

that value is your total time

divide you total distance (2L) by total time (7.95L/15.59) and the Ls cancel out and you get

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Explanation:

7 0
3 years ago
A cork able to float on water because it is
Schach [20]
A cork is less dense
8 0
3 years ago
In the lab you place a beaker that is half full of water (density pw ) on a scale. You now use a light string to suspend a piece
Radda [10]

Answer:

N2- N1 = \rho_{w}  V g

Explanation:

Let's use for this exercised the equilibrium relationship

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        N -W = 0

        N = W = mg

Let's use density redefinition

       ρ = m / v

       m = ρ V

       N₁ = (ρ V) g

Repeat for when the liquid is submerged, in this case an upward thrust appears as a result of the water dispensed (rgow)

        N₂ + B - W = 0

        N₂ = W - B

        B = m_{water} g

        \rho_{w} = m / V

         m_{w}  =  \rho_{w}  V

        N = ρ V g -  \rho_{w}  Vg

        N2 = N1 +   \rho_{w}  V g

        N2- N1 = \rho_{w}  V g

6 0
3 years ago
An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius
Olin [163]

Answer:

g'=40\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=0.5\ kg
  • weight of the object on planet x, W=20\ N
  • radius of the planet, R=4\times10^6\ m
  • radial distance between the planet and the object, r=2\times 10^6\ m

<u>Now free fall acceleration on planet X:</u>

W=m.g'

20=0.5\times g'

g'=40\ m.s^{-2} irrespective of the height.

8 0
3 years ago
Read 2 more answers
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