Hey there!
Molar mass of O3 = 47.9982 g/mol
therefore:
1 mole O₃ --------------------- 47.9982 g
moles O₃ ---------------------- 24 g
moles O₃ = 24 x 1 / 47.9982
moles O₃ = 24 / 47.9982
moles O₃ = 0.500 moles
Hope this helps!
<u>Ans 1:</u>
Ammonia is not collected over water since it is highly soluble in water
<u>Ans 2:</u>
Ammonia gas is lighter than air and hence collected by the downward displacement of air.
<u>Ans 3:</u>
The carbon dioxide is very cold as it comes out of the extinguisher, so it cools the fuel as well.
<u>Ans 4:</u>
H₂SO₄ is not used in the preparation of carbon dioxide Because the calcium sulphate formed is insoluble in water. So, CO₂ will not form.
<u>Ans 5:</u>
The opening of hard glass test tube is slanted down during laboratory preparation of ammonia gas because Ammonia gas is not collected in the gas jar by upward displacement of air because it is lighter than air
<u>Ans 6:</u>
Magnesium is reactive enough to be combusted and oxidized in a reaction with carbon dioxide:
The magnesium strip burns brightly in the air, but continues to burn in the carbon dioxide environment
<u>-</u><u>TheUnkownScientist</u>
Condensation would occur at that time
<u>Answer:</u> The correct answer is Option C.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of methane = 48.2 g
Molar mass of methane = 16 g/mol
Putting values in above equation, we get:
According to mole concept:
1 mole of compound contains 
number of molecules.
So, 3.0125 moles of methane will contain = 
number of molecules.
Hence, the correct answer is Option C.
