Let us assume that this molecule is 100 percent ionic. In that case, the charges are distinguished by a bond length.
h = Q × r
= (160 × 10⁻¹⁹ c) (127 × 10⁻¹² m) (10 / 3.336 × 10⁻³⁰ cm)
= 6.09 D.
The actual dipole moment is = 1.08 D
Therefore, the percent ionic character is,
= 1.08 D / 6.09 D × 100
= 17.7 %.
To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.
I believe it is low frequency.
