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Mademuasel [1]
3 years ago
9

Compare and contrast the moon and the moons of other planets.

Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer:

The Moon of the Earth has some similarities, but also lot of differences with the other natural satellites in the Solar system.

The Moon is rocky, covered with dust, has lot of craters from asteroids and meteorites. Most of the planets in the solar system are actually gassy, frozen, and the craters tend to be very rare.

Compared to the planet around which it spins, the Earth, the Moon is actually very large, even though it is nowhere as large as some other moons in the Solar System. All the other moons tend to be much smaller in comparison the the planets around which they spin.

The Moon also has very low gravitational pull and very small mass for its size, and the reason for that is still not clear. All the other moons have gravitational pulls and masses that are expected by their size.

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I’LL MAKE YOU BRAINLIEST+ FREE POINTS
vladimir2022 [97]

Answer:

The solution's new volume is 1.68 L

Explanation:

Dilution is the procedure to prepare a less concentrated solution from a more concentrated one, and simply consists of adding more solvent. So, in a dilution the amount of solute does not vary, but the volume of the solvent varies.

In summary, a dilution is a lower concentration solution than the original.

The way to do the calculations in a dilution is through the expression:

Ci*Vi=Cf*Vf

where C and V are concentration and volume, respectively; and the i and f subscripts indicate initial and final respectively.

In this case, being:

  • Ci= 7 M
  • Vi= 0.60 L
  • Cf= 2.5 M
  • Vf=?

Replacing:

7 M*0.60 L= 2.5 M* Vf

Solving:

Vf=\frac{7 M*0.60 L}{2.5 M}

Vf= 1.68 L

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3 years ago
A scientist performs an experiment in which a radium–226 (Ra–226) atom decays into radon–222 (Rn–222). The scientist concludes t
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Answer:

B)

Explanation:

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Answer:

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Explanation:

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For the following electron-transfer reaction:
creativ13 [48]

Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

Mn changes from 0, in the ground state to Mn²⁺.

The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)  

Now we sum, and we can cancel the electrons:

2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻

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69.047% is the answer to this question
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