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3 years ago

The Law of Multiple Proportions states that ____.

Chemistry

1 answer:

harkovskaia [24]3 years ago

5 0

Answer: when two elements combine, A and B, the ratio of the weight of B combining with A is always a whole number

Explanation:

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Write the reaction rate expressions for the<br> following reactions?<br> 2H2+O2_____2H2O

Nezavi [6.7K]

Answer:

see attachment

Explanation:

3 0

3 years ago

Some contaminants enter the water from commercial farming, while other problems are an indirect result of these contaminants. Wh

maks197457 [2]

The indirect result of contaminants from commercial farming is algae.

<h3>What is Contaminant?</h3>

Contaminant is a substance either chemical, physical that is very toxic or harmful to living organisms, when it is released into air, water, soil or food.

Contaminant are poisionus substance that are not deliberately or are deliberately introduced to space . This contaminants make things impure and they are highly poisionus.

Therefore, The indirect result of contaminants from commercial farming is algae.

Learn more about contaminant below.

brainly.com/question/465199

3 0

2 years ago

A student wants to determine what type of cereal his classmates like best he buys three of his favorite puffed rice cereals and

kogti [31]

D. the student's conclusion shows experimental bias

4 0

3 years ago

How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?

vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0

3 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago