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a_sh-v [17]
4 years ago
13

You’re engineering an energy-efficient house that will require an average of 6.85 kW to heat on cold winter days. You’ve designe

d a photovoltaic system for electric power, which will supply on average 2.32 kW. You propose to heat the house with an electri-cally operated groundwater-based heat pump. What should you specify as the minimum acceptable COP for the pump if the pho-tovoltaic system supplies its energy?
Engineering
1 answer:
Oxana [17]4 years ago
8 0

Answer:

2.95 approximately 3

Explanation:

For a heat pump,

COP = Q/W

Where Q = power needed for heating process

W = power input into heat pump.

Power for heating Q = 6.85 kW

Proposed power input to heat pump W = 2.32 kW

Minimum COP = 6.85/2.32 = 2.95

Approximately 3

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A river has an average rate of water flow of 59.6 M3/s. This river has three tributaries, tributary A, B and C, which account fo
Fiesta28 [93]

Answer:

50421.6 m³

Explanation:

The river has an average rate of water flow of 59.6 m³/s.

Tributary B accounts for 47% of the rate of water flow. Therefore the rate of water flow through tributary B is:

Flow rate of water through tributary B = 47% of 59.6 m³/s = 0.47 * 59.6 m³/s = 28.012 m³/s

The volume of water that has been discharged through tributary B = Flow rate of water through tributary B * time taken

time = 30 minutes = 30 minutes * 60 seconds / minute = 1800 seconds

The volume of water that has been discharged through tributary B in 30 seconds = 28.012 m³/s * 1800 seconds = 50421.6 m³

3 0
3 years ago
Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. A divisor is a numb
tekilochka [14]

Answer:

// Program is written in C++

// Comments are used to explain some lines

// Only the required function is written. The main method is excluded.

#include<bits/stdc++.h>

#include<iostream>

using namespace std;

int divSum(int num)

{

// The next line declares the final result of summation of divisors. The variable declared is also

//initialised to 0

int result = 0;

// find all numbers which divide 'num'

for (int i=2; i<=(num/2); i++)

{

// if 'i' is divisor of 'num'

if (num%i==0)

{

if (i==(num/i))

result += i; //add divisor to result

else

result += (i + num/i); //add divisor to result

}

}

cout<<result+1;

}

6 0
3 years ago
A good rule of thumb in hazardous conditions is to _____.
Aloiza [94]

Answer:

C. Have your hazard lights on

Explanation:

Speeding up will cause an accident

Counter steering is not easy to do

Slowing down my result in you being rear ended

5 0
3 years ago
Read 2 more answers
A list is sorted in ascending order if it is empty or each item except the last one is less than or equal to its successor. HERE
Free_Kalibri [48]

Using the knowledge of computational language in python it is possible to write a code that writes a list and defines the arrange.

<h3>Writing code in python:</h3>

<em>def isSorted(lyst):</em>

<em>if len(lyst) >= 0 and len(lyst) < 2:</em>

<em>return True</em>

<em>else:</em>

<em>for i in range(len(lyst)-1):</em>

<em>if lyst[i] > lyst[i+1]:</em>

<em>return False</em>

<em>return True</em>

<em>def main():</em>

<em>lyst = []</em>

<em>print(isSorted(lyst))</em>

<em>lyst = [1]</em>

<em>print(isSorted(lyst))</em>

<em>lyst = list(range(10))</em>

<em>print(isSorted(lyst))</em>

<em>lyst[9] = 3</em>

<em>print(isSorted(lyst))</em>

<em>main()</em>

See more about python at brainly.com/question/18502436

#SPJ1

7 0
2 years ago
Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW o
jekas [21]

Complete Question

Complete Question is attached below.

Answer:

V'=5m/s

Explanation:

From the question we are told that:

Diameter d=0.10m

Power P=4.0kW

Head loss \mu=10m

 \frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu

 \frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10

 H_m=(\frac{200*10^3}{1000*9.8}-10)

 H_m=10.39m

Generally the equation for Power is mathematically given by

 P=\rho gQH_m

Therefore

 Q=\frac{P}{\rho g H_m}

 Q=\frac{4*10^4}{1000*9.81*10.9}

 Q=0.03935m^3/sec

Since

 Q=AV'

Where

 A=\pi r^2\\A=3.142 (0.05)^2

 A=7.85*10^{-3}

Therefore

 V'=\frac{0.03935m^3/sec}{7.85*10^{-3}}

 V'=5m/s

5 0
3 years ago
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