Ask question

Ask question

All categories

anzhelika [568]

3 years ago

15

A beam spans 40 feet and carries a uniformly distributed dead load equal to 2.2 klf (not including beam self-weight) and a live

load equal to 3.6 klf.
The beam is laterally braced only at the supports and at the midpoint of the span.

Select the lightest W-shape that is adequate for flexure.

Clearly state the controlling limit state and be specific.

1 answer:

salantis [7]3 years ago

6 0

Answer:

A beam is a structural member that is subjected primarily to transverse loads ... stress equal to σy, then the section Moment - Curvature (M-φ) response for .... Example 2.2 Design a simply supported beam subjected to uniformly distributed dead ... (live load). • Step I. Calculate the factored design loads (without self-weight).

Explanation:

You might be interested in

A soil sample has a moist unit weight of 117 pcf, a moisture content of 17 percent, and soil particles with a specific gravity o

nikklg [1K]

Answer:

(A) Dry unit weight. = 15.71 kN/m³ =100.91 pcf

(B) Porosity = 40.82 %

(C) Degree of saturation = 66.52 %

(D) Weight of water, in pounds per cubic foot, to be added to reach full saturation = 81.22 pcf

Explanation:

(A) γd = $\frac{\gamma }{1+w}$ = $\frac{18.379}{1+.17} = 15.71$ KN/m³

(B) $\gamma _d =\frac{G_{s}* \gamma _w }{1+e}$ therefore $1+e = \frac{G_{s}* \gamma _w }{\gamma _d }$ $\frac{2.7*9.81}{15.71} =$ 1.69

Therefore e = 0.69 and

Porososity n = $\frac{e}{1+e}$ = $\frac{0.69}{1+0.69}$ × 100% = 40.82 %

(C) $S_{e} = w*G_{s}$ therefore S = $\frac{w*G_{s}}{e}$ = $\frac{0.17*9.81}{0.69}$ ×100 = 66.52 %

(D) $\gamma _{sat} =\frac{(G_{s}+e) \gamma_{w} }{1+e}$ = $\frac{(2.7+0.69)9.81}{1+0.69}$ = 19.68 kN/m³

The required amount of water is found from γ =ρ×g

ρ mass of water = $\frac{\gamma}{g} = \frac{(19.68-18.38)\frac{kN}{m^{3} } }{9.81 kg\frac{m}{s^{2} } } *\frac{1000 N}{kN} *\frac{9.81 kg\frac{m}{s^{2} } }{N} = 1301 \frac{kg}{m^{3} }$

1 kg/m³ = 0.062 pcf therefore 1301 kg/m³ = 1301 ×0.062 pcf or 81.22 pcf

6 0

3 years ago

In manufacturing a particular set of motor shafts, only shaft diameters of between 38.00 and 37.50 mm are usable. If the process

Masteriza [31]

Answer:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

$X \sim N(37.8,0.12)$

Where $\mu=37.8$ and $\sigma=0.12$

We are interested on this probability

$P(37.5$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

4 0

3 years ago

Steam at 6 MPa and 5008C enters a two-stage adiabatic turbine at a rate of 15 kg/s. 10 percent of the steam is extracted at the

loris [4]

Answer:

Bubblebutt

Explanation:

4 0

3 years ago

The shear flow at the point depends on the value of Q for the portion of the upper flange to the right of the point. Calculate t

Ostrovityanka [42]

Q)The shear flow at a point is given by q = 1 of 2 An I-beam has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm, and flange thickness t = 12 mm, For the given point The shear flow at the point depends on the value of Q for the portion of the upper flange to the right of the point. Calculate the value of Q. Express your answer with appropriate units to three significant figures.( <u>I have also attached the diagram for better understanding)</u>

Answer:

Q = 56400 mm^3

Explanation:

<u>I have given the explanation in the attached file below.</u>

6 0

3 years ago

List three types of concurrent engineering in manufacturing.

klio [65]

Answer:

A famous example of concurrent engineering is the development of the Boeing 777 commercial aircraft. The aircraft was designed and built by geographically distributed companies that worked entirely on a common product database of C A TIA without building physical mock-ups but with digital product definitions.

8 0

3 years ago