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schepotkina [342]
3 years ago
11

How do i get a used eraser out of a mechanical pencil

Engineering
2 answers:
timurjin [86]3 years ago
4 0

Answer:

Use a screw or corkscrew.  Screw it into the eraser, then pull.

Arada [10]3 years ago
3 0

Cut out the eraser with a craft knife if it is already way inside.

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If you log into the admin account on windows 10, will the admin be notified ? ​
professor190 [17]

Answer:

Just message the Admin,

Ok.

6 0
3 years ago
Read 2 more answers
determine the position d of the 6- kn load so that the average normal stress in each rod is the same.
Zinaida [17]

The load is placed at distance 0.4 L from the end of $$12 \mathrm{~mm}^{2} $ area.

<h3>What is meant by torque?</h3>

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is torque.

Let the beam is of length L

Now the stress on both the end is the same now we can say that torque on the beam due to two forces must be zero

$N_1 * x=N_2 *(L-x)$

also, we know that stress at both ends are same

$\frac{N_1}{12}=\frac{N_2}{8}$

$2 * N_1=3 * N_2$

Now from two equations we have

$\frac{3}{2} N_2 * x=N_2 *(L-x)

solving the above equation we have

$x=\frac{2}{5} L

so the load is placed at distance 0.4 L from the end of $$12 \mathrm{~mm}^{2} $ area.

The complete question is:

47. the beam is supported by two rods ab and cd that have cross-sectional areas of $$12mm^2 and $$8mm^2, respectively. determine the position d of the 6-kn load so that the average normal stress in each rod is the same.

To learn more about torque refer to:

brainly.com/question/20691242

#SPJ4

7 0
2 years ago
Source water pollution in Madagascar
vodka [1.7K]

Answer:

What is the question?

Explanation:

7 0
3 years ago
Sun of first 1 nayural numbers​
marin [14]

Answer:

the answer is

n(n + 1)  \div 2

n(n+1)/2

4 0
2 years ago
Read 2 more answers
An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through th
sp2606 [1]

Answer:

<em> - 14.943 W/m^2K  ( negative sign indicates cooling ) </em>

Explanation:

Given data:

Area of FPC = 4 m^2

temp of water = 60°C

flow rate = 0.06 l/s

ambient temperature = 8°C

exit temperature = 49°C

<u>Calculate the overall heat loss coefficient </u>

Note : heat lost by water = heat loss through convection

m*Cp*dT  = h*A * ( T - To )

∴ dT / T - To = h*A / m*Cp  ( integrate the relation )

In ( \frac{49-8}{60-8} ) =  h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )

In ( 41 / 52 ) = 0.0159*h

hence h = - 0.2376 / 0.0159

              = - 14.943  W/m^2K  ( heat loss coefficient )

7 0
2 years ago
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