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schepotkina [342]
3 years ago
11

How do i get a used eraser out of a mechanical pencil

Engineering
2 answers:
timurjin [86]3 years ago
4 0

Answer:

Use a screw or corkscrew.  Screw it into the eraser, then pull.

Arada [10]3 years ago
3 0

Cut out the eraser with a craft knife if it is already way inside.

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A construction crew lifts approximately 400 lb. of material several times during a day from a flatbed truck to a 25 ft. rooftop.
Irina18 [472]

Answer:

2ib

Explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

5 0
2 years ago
It is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water entering at 20 °C?
vovangra [49]

Answer:

Yes, it is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water that is entering at 20 °C because this temperature (20 °C) of the external cooling water is less than the saturation temperature of steam which is which is 45.81 °C, and heated by a boiler; as a result of this condition, coupled with the assumption that the turbine, pump, and interconnecting tube are adiabatic, and the condenser exchanges its heat with the external cooling river water, it possible to maintain a pressure of 10 kPa.

5 0
3 years ago
As cylinder pressure and heat increase due to an increased load condition, the fuel injection management system must ___________
Temka [501]

possible Answers:

Compensate ⭐⭐⭐⭐⭐

Adjust            ⭐⭐⭐⭐⭐

regulate         ⭐⭐⭐⭐

tune               ⭐⭐⭐

calibrate        ⭐⭐⭐

balance         ⭐⭐

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6 0
2 years ago
Timken rates its bearings for 3000 hours at 500 rev/min. Determine the catalog rating for a ball bearing running for 10000 hours
svet-max [94.6K]

Answer:

C₁₀ = 6.3 KN

Explanation:

The catalog rating of a bearing can be found by using the following formula:

C₁₀ = F [Ln/L₀n₀]^1/3

where,

C₁₀ = Catalog Rating = ?

F = Design Load = 2.75 KN

L = Design Life = 1800 rev/min

n = No. of Hours Desired = 10000 h

L₀ = Rating Life = 500 rev/min

n₀ = No. of Hours Rated = 3000 h

Therefore,

C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3

C₁₀ = (2.75 KN)(2.289)

<u>C₁₀ = 6.3 KN</u>

3 0
3 years ago
In a TDM communication example, 15 voice signals are badlimited to 5kHz and transmitted simultaneously using PAM. What is a prel
MA_775_DIABLO [31]

Answer:

Option D

160 kHz

Explanation:

Since we must use at least one synchronization bit, total message signal is 15+1=16

The minimum sampling frequency, fs=2fm=2(5)=10 kHz

Bandwith, BW required is given by

BW=Nfs=16(10)=160 kHz

5 0
3 years ago
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