Answer:
If pressure increases, then volume decreases and vice versa, when temperature is held constant.” When pressure increases, the same number of molecules, or matter, are being forced closer together to occupy a shrinking space, their volume decreasing while their density correspondingly increases.
Explanation:
Answer:
Q1. a) 4Al + 3O₂ ➟ 2Al₂O₃
b) 7.4 moles
c) 11.1 moles
Explanation:
To balance an equation, ensure that the total number of atoms of each element on both sides are equal.
Al + O₂ ➟ Al₂O₃
On the left side of the arrow, you would find the reactants while the product(s) is found on the left hand side.
<u>Reactants</u>
Al atoms: 1
O atoms: 2
<u>Product</u>
Al atoms: 2
O atoms: 3
After balancing,
4Al + 3O₂ ➟ 2Al₂O₃
We have 4 Al atoms and 6 O atoms on both sides.
b) The balanced equation tells us the mole ratio of Al to Al₂O₃.
Al: Al₂O₃
= 4: 2 (÷2 throughout)
= 2: 1
This means that for every 1 mole of Al₂O₃, 2 moles of Al is needed.
Since we need 3.7 moles of Al₂O₃,
number of moles of Al needed
= 2×3.7
= 7.4
c) 4Al + 3O₂ ➟ 2Al₂O₃
For every 4 moles of Al, 3 moles of O are needed.
For each mole of Al,
number of moles of O needed
= 3÷4
= 0.75
For 14.8 moles of Al,
number of moles of O required
= 0.75 ×14.8
= 11.1
Answer:
Full moon
Explanation:
Went from cresent to half, meaning it should go to full moon next~
Answer:
19.2g
Explanation:
The equation of the reaction is;
Li3N(s) +3H2O(l) ---->NH3(g) +3LiOH(aq)
From Avogadro's law we know that 1 mole of any gas occupies a volume of 22.4 L under standard conditions.
It is also clear from the equation that 1 mole of lithium nitride produces 1 mole of ammonia occupying 22.4L volume
Hence;
1 mole of Lithium nitride yields 22.4 L of ammonia
x moles of lithium nitride yields 12.26L of ammonia
x= 12.26×1/22.4
x= 0.55 moles of lithium nitride
Molar mass of lithium nitride= 34.83 g/mol
Mass of lithium nitride = number of moles × molar mass
Mass of lithium nitride= 0.55 moles × 34.83 g/mol
Mass of lithium nitride = 19.2g