What is the molarity of 5.39 grams of CaCl2 dissolved in 609 mL of water? (molar mass = 110.98 g/mol)
1 answer:
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<u>Answer:</u> The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of hex-3-ene = 5.84 g
Molar mass of hex-3-ene = 82.14 g/mol
Putting values in equation 1, we get:
The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:
By Stoichiometry of the reaction:
1 mole of hex-3-ene produces 1 mole of 3-hexanol
So, 0.0711 moles of hex-3-ene will produce = of 3-hexanol
Now, calculating the mass of 3-hexanol from equation 1, we get:
Molar mass of 3-hexanol = 102.2 g/mol
Moles of 3-hexanol = 0.0711 moles
Putting values in equation 1, we get:
To calculate the percentage yield of 3-hexanol, we use the equation:
Experimental yield of 3-hexanol = 4.33 g
Theoretical yield of 3-hexanol = 7.27 g
Putting values in above equation, we get:
Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
Answer:
Explanation:
Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment
In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.
Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:
keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.
Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.
Answer: 23,199 J
Explanation:
