What is the molarity of 5.39 grams of CaCl2 dissolved in 609 mL of water? (molar mass = 110.98 g/mol)

Mashutka [201]

Answer:

High explosives do not need to be contained to make their bang. Nitroglycerine, trinitrotoluene, and RDX are high explosives.

Explanation:

6 0

2 years ago

Why are the offspring produced by sexual reproduction different than their parents?

Arada [10]

Answer:

Offspring inherit different amounts of DNA from both their parents?

Explanation:

3 0

2 years ago

Taylor, a MIC 206 student needs to determine the OCD of a sample of Escherichia coli. She performed dilutions using four 9 ml di

Troyanec [42]

Answer:

1.37 x $10^6$ CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of $10^{-4}$ .

Next is to divide the colony forming unit from the dilution by the dilution factor:

137/ $10^{-4}$ = 137 x $10^4$

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

137 x $10^4$ /1 = 1.37 x $10^6$

Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x $10^6$ .

cfu/ml = (no. of colonies x dilution factor) / volume of culture plate

7 0

3 years ago

There are four hundred participants in the local Thanksgiving 5K race. If 51% of the participants are female, what is the ratio

Paha777 [63]

Answer:

51:49 is the ratio of female participants to male participants.

Explanation:

Percentage of females in the race = 51 %

Percentage of males in the race = 100% - 51 % = 49%

Total participants in race = 400

Number of women participants = $51% of 400=\frac{51}{100}\times 400=204$

Number of men participants = $49% of 400=\frac{49}{100}\times 400=196$

Ratio of female participants to male participants :

$\frac{204}{196}=\frac{51}{49}=51:49$

5 0

2 years ago

K for enolization of 2,4-cyclohexadienone is about 1013. Explain why the enol is so much more stable than the keto tautomer.

torisob [31]

Answer:

Because the value of K is huge.

Explanation:

The tautomer is a kind of isomer in which exist an equilibrium between a ketone and an enol, or between an aldehyde and an enol. So, in the enolization, the ketone is the reactant and the enol is the product.

The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

So, the ketone is unstable and forms in a great amount the more stable product, the enol.

4 0

2 years ago