a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
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<h3>
Answer: 10 kg</h3>
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Work Shown:
We have these variables
- p = momentum = 25 kg*m/s
- m = mass = unknown
- v = velocity = 2.5 meters per second
Solving for the mass gets us...
p = m*v
25 = m*2.5
25/2.5 = m
10 = m
m = 10
The mass of the horse is 10 kg.
A lot would happen depends on which perspective you look at it from. Less incoming solar radiation means that there is a greater possibility of the surface temperature of earth reducing. there would be a cooling effect. And it could be major cooling in certain part of the world depending on milankovitch cycles. We know that the amount of light or solar radiation that reaches the earth is unequal in different parts of the world because of the obliquity, eccentricity, and precession of the earth. But, in general you would most likely see a cooling trend around the world and in some parts it would be extreme. In Canada or in the North is general, winters would become even more cooler or colder... winters would become longer perhaps, And summers would 've cooler. on the contrary to what most believe, you would most likely see a decline in precipitation such as snow or rain because this is mostly caused or intensified by warming temperatures. Life would be probably very similar to that of the Pleistocene epoch. how would humans respond to this change... Well most likely they would try to use their tech to control weather because they already do to a smaller proportion.
hope that helps a bit! :)
P=mv
pi =pf
(68x2.79)+(131x0) = 199v
v= 0.95 m/s
The initial speed of the automobile is 49.84km/hr
<u>Explanation:</u>
Given:
Acceleration, a = 1.77 m/s²
Time, t = 6s
Final speed, v = 88 km/h
v = 88 X 0.278 m/s
v = 24.464 m/s
Initial speed, u = ?
We know,
v = u + at
On substituting the value in the formula we get:
24.464 = u + (1.77 X 6)
24.464 = u + 10.62
u = 24.464 - 10.62 m/s
u = 13.844 m/s
Converting u = 13.844 m/s to km/hr
1 m/s = 3.6 km/hr
13.844 m/s = 13.844 X 3.6 km/hr
u = 49.84 km/hr
Therefore, the initial speed of the automobile is 49.84km/hr
