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4 years ago

Can you change the weight of something without changing the mass?

Physics

1 answer:

svlad2 [7]4 years ago

3 0

yes because your mass doesn't change but your weight can

ex- if you travel to Saturn your weight would change but your mass would stay the same

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Are you familiar with that?

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3 years ago

An electron and a proton

dem82 [27]

Answer:

If you are asking the definition here is your answer:--

Explanation:

Electrons are negatively charged particles that revolve around the nucleus of an atom. In QFT(Quantum field theory) Electrons are vibration of space in the positive energy field.

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4 years ago

An athlete at high performance inhales 4.0L of air at 1 atm and 298 K. The inhaled and exhaled air contain 0.5% and 6.2% by volu

LenaWriter [7]

To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.

An athlete at high performance inhales 4.0L of air at 1atm and 298K.

The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.

During inhalation, volume of water taken is

$V_i = (4L)(0.5\%)$

$V_i = 0.02L$

During exhalation, volume of water expelled is

$V_e = (4L)(6.2\%)$

$V_e = 0.248L$

During 40 breathes, total volume of water taken is

$V_{it} = (40L)(0.02L) = 0.8L$

During 40 breathes, total volume of water expelled out is

$V_{et} = (40L)(0.248L) = 9.92L$

Therefore resultant volume of water expelled out from the lung is

$\Delta V = 9.92L-0.8L = 9.12$

From the body through the lung we have that

$n = \frac{PV}{RT}$

Here,

P = Pressure

R= Gas ideal constant

T= Temperature

V = Volume

Replacing,

$n = \frac{(1atm)(9.12L)}{(8.314J/mol \cdot K)(298K)}$

$n = 0.373mol/min$

Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min

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4 years ago

Dandre expands 120w of power in moving a couch 15 meters in 5 seconds how much force does he exert ?

netineya [11]

Answer:

The answer is 40 N for APX

Explanation:

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3 years ago

A small 22 kilogram canoe is floating downriver at a speed of 3 m/s. What is the canoe's kinetic energy?

amid [387]

Kinetic energy can be calculated using the following rule:
kinetic energy = 0.5*m*v^2 where:
m is the mass = 22 kg
v is the velocity = 3 m/sec

Substitute with the givens in the above equation to get the kinetic energy as follows:
kinetic energy = 0.5(22)(3)^2
kinetic energy = 99 Joules

4 0

3 years ago

Read 2 more answers