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olganol [36]
3 years ago
15

Which of the following statements about gravitational potential energy is not true?

Physics
1 answer:
nevsk [136]3 years ago
3 0

Answer:

B and D

Explanation

Gravitational potential energy does not relate to graphs and it is about a moving object so b and d would not be correct

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What happens to particles of a substance as its temperature increases? A the average kinetic energy increases B the average kine
Gemiola [76]
The answer is A. When the the temperature increases the kinetic energy increases
6 0
3 years ago
An object moving north with an initial velocity of 14m/s accelerates 5m/s squared for 20 seconds. What is the final velocity of
Gemiola [76]

Since it moves 5 m/s faster every second, after 20 seconds it's moving 100 m/s faster than when it started speeding up.

If it was moving at 14 m/s when the acceleration began, it's moving at 114 m/s at the end of the 20 seconds.  Its velocity is <em>114 m/s North.</em>

That's 255 mph !

4 0
3 years ago
The IMA of a lever can be increased by decreasing the length between the applied effort and the pivot.
mina [271]
<span>We never really used the acronym "IMA", or ideal mechanical advantage, but I'm assuming you are trying to increase the leverage and ease the effort. If so, the answer is false. You want larger movement on the effort side, and smaller movement on the resistant side of the fulcrum.</span>
3 0
3 years ago
Read 2 more answers
Tectonic plates are large segments of the earth's crust that move slowly. Suppose that one such plate has an average speed of 4.
Lelechka [254]

Answer:

1.267 nanometers.

Explanation:

From the question,

Speed = distance/time.

S = d/t.................. Equation 1

Make d the subject of the equation,

d = S×t ............................... Equation 2

Given: S = 4.0 cm/year, t = 1 seconds = 3.17×10⁻⁸ years

Substitute into equation 2

d = 4×3.17×10⁻⁸ =

12.68×10⁻⁸ cm = 12.67×10⁻⁸×10⁷

d = 1.267 nanometers.

Hence the Tectonic plates move 1.267 nanometers.

7 0
3 years ago
A migrating bird flew across a lake at an average speed of 18 meters per second. Was the distance that the bird flew across the
Natasha_Volkova [10]

Answer:

It cannot be said with 100% guarantee.

Explanation:

Since bird is travelling with 18 meters per second, that means that it covers a distance of 18 meters in 1 second.

for part 1 we convert 20 minutes into seconds, thus, 20 * 60 = 1200 seconds.

Distance covered in 1200 seconds will be:

S = v * t (S is distance , v is speed, t is time)

18 * 1200 = 21600 meters = 21.6 Kilometers

If the bird took less than 20 minutes than distance covered would be less than 21.6 Kilometer which could be greater than or lesser than 21 Kilometers. On average we can say that the distance bird travelled will be less than 21 Kilometer. But it is not definite.

For part B convert 0.4 hours into seconds to find the distance it travelled.

0.4 * 60 * 60 = 1440 seconds

Distance covered will be

18 * 1440 = 25920 meters = 25.9 Kilo meters.

Again, if the bird takes less than 0.4 hours to cover the lake, the lake will be less than 25.9 kilometers long. This means that it could be greater than or lesser than 21 kilometers. It cannot be definitive

7 0
4 years ago
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