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Brums [2.3K]
3 years ago
7

A vertical spring with spring stiffness constant 305 N/m oscillates with an amplitude of 28.0 cm when 0.235 kg hangs from it. Th

e mass passes through the equilibrium point (y=0) with positive velocity at t=0. Positive direction of y-axis is downward.What equation describes this motion as a function of time?
Physics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

The function that describe the motion in the time

y (t) = 0.28m * sin ( 36.025 * t)

Explanation:

The angular frequency of oscillation of the spring

w = √k/m

w = √305 N/m / 0.235 kg

w = 36.025 rad / s

To determine the function of the motion knowing as a motion oscillation in a amplitude a frequency

y(t) = A * sin (w t )

So

A = 28.0 cm * 1 m / 100 cm = 0.28 m

So replacing to determine the function of the motion in the time

y (t) = A sin (w t)

y (t) = 0.28m * sin ( 36.025 * t)

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Answer:

a) V_{2/1}=0.8m/s

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Explanation:

For part (a):

V_{2/1} = V_{2} - V_{1} = 0.8m/s

For part (b) we will calculate the amount of time that takes both runners to cross the finish line:

t_{1} = \frac{X_{1}}{V_{1}}=\frac{250}{3.45}=72.46s

t_{2} = \frac{X_{2}}{V_{2}}=\frac{250+45}{4.25}=69.41s

Since it takes less time to the second runner to cross the finish line, we can say the she won the race.

For part (c), we know how much time it takes the second runner to win, so we just need the position of the first runner in that moment:

X1 = V1*t2 = 239.46m  Since the finish line was 250m away:

d = 250m - 239.46m = 10.54m

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What wave on the electromagnetic spectrum has the highest frequency?
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Answer:

Explanation:

Answer: Gamma rays

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Higher frequency rays have the highest energies.

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Gamma radiations are obtained from the decay of the atomic nucleus.

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It has the smallest wavelength and highest energy.

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Two students make the following claims:
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Answer:

E. Student 1 is correct, because as θ is increased, h is the same.

Explanation:

Here we have the object of a certain mass falling under gravity so the force acting on the it will depend on mass of the object and the acceleration due to gravity.

Mathematically:

F=m.g

As we know that the work done is evaluated as the force applied on a body and the displacement of the body in the direction of the force.

And for work we have:

W=F.s\cos\theta

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s= displacement of the object

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Given that the height of the object is same in each trail of falling object under the gravity be it a free-fall or the incline plane.

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A 8.4-mH inductor carries a current I = Imaxsin ωt, with Imax = 4.00 A and f = ω/2π = 60.0 Hz. What is the self-induced emf as a
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Answer:

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Given that

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We know that self induce E given as

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E= -3.166 cosωt   V

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