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eimsori [14]
3 years ago
15

g Design single input op-amp circuits with with closed loop gains of −10, +10, +1 and −1. Use 10kΩ for the feedback resistor Rf

in your designs. What type of feedback is used in the ±10 gain amplifiers? Explain with appropriate equations the effect of feedback on input and output resistances of the amplifier circuits.
Physics
1 answer:
Ronch [10]3 years ago
6 0

Explanation:

For Gain of −10

Inverting op-amp gain is given by

Gain=V_{out} /V_{in} = -R_{f} /R_{in}

The negative sign represents output signal being phase shifted by 180°

-10=-10/R_{in}

R_{in} =-10k/-10

R_{in} =1kΩ  

For Gain of −1

Gain= -R_{f} /R_{in}

-1=-10k/R_{in}

R_{in} =-10k/-1

R_{in} =10kΩ

For Gain of +10

Non-inverting op-amp gain is given by

Gain=V_{out} /V_{in}  =1 + R_{f}/R_{in}

10=1+(10k/R_{in})

10-1=10k/R_{in}

9=10k/R_{in}

R_{in} =10k/9

R_{in} = 1.11kΩ

For Gain of +1

To get a Gain of +1, make R_{f}=0  which results in R_{in} = ∞

The output is directly connected to the input which makes V_{out} equal to V_{in}Therefore, giving a gain of exactly 1.

V_{out} =G*V_{in}

G=1

This kind of design configuration is also known as Voltage Follower.

Negative feedback is being used to design these op-amp amplifiers.

\frac{V_{out}}{V_{in}}  =\frac{G}{1+\beta G}

Negative feedback increases the stability at the cost of reduced gain.

The gain is reduced by a factor of 1+\beta G  

Negative feedback reduces noise and distortion and improves frequency response of the amplifier.

An ideal op-amp should have infinite input resistance and zero output resistance. Negative feedback increases the input impedance and reduces the output impedance.

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4 0
2 years ago
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Sergio039 [100]
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5 0
3 years ago
A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is
HACTEHA [7]

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;

mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

5 0
3 years ago
Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8
Kamila [148]

Answer:

34.6 m/s

Explanation:

From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg

Final mass will be 31.5+25.9=57.4 kg

From formula of momentum

M1v1=m2v2

Making v2 the subject of the formula then

V2=\frac {M1v1}{m2}

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then

V2=\frac {100.2 kg\times 19.8 m/s}{57.4 kg}=34.56376 m/s\approx 34.6 m/s

4 0
3 years ago
Romeo traveled by a 900 kg horse from Manitua to Verona accelerating at the rate of 20 km/hr. With what force is Romeo moving at
Nookie1986 [14]

Answer:

Force(Romeo moving) = 5,000 N

Explanation:

Given:

Mass of horse = 900 kg

Acceleration = 20 km/hr

Find:

Force(Romeo moving)

Computation:

Acceleration = 20 km/hr

Acceleration in m/s = 20 / 3.6 = 5.555556 m/s²

Force = m x a

Force(Romeo moving) = 900 x 5.555556

Force(Romeo moving) = 5,000 N

3 0
3 years ago
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