Answer:
Radio waves have the longest wavelengths in the EM spectrum, according to NASA, ranging from about 0.04 inches (1 millimeter) to more than 62 miles (100 kilometers).
Band Frequency range Wavelength range
Very Low Frequency (VLF) 3 to 30 kHz 10 to 100 km
Low Frequency (LF) 30 to 300 kHz 1 m to 10 km
Explanation:
Answer:
Explanation: N2 Nitrogen, O2 Oxygen, Ar does not form molecules
Answer:
35.792 N
Explanation:
d = Diameter of rod = 2.7 cm
h = Length of rod = 81.7 cm
= Density of rod = 7800 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Volume of rod

Mass is given by

Weight is given by

The weight of the rod is 35.792 N
The distance to the water is the same for both ... call it s meters
They both take 1.6 s to reach the water ... so t = 1.6 seconds
They both step off the bridge ... so both have an initial vertical velocity is 0 m/s
Just consider the vertical motion and take DOWN as the positive direction
a = 9.8 m/s²
s = v(i)t + (1/2)at²
s = 0 + (1/2) * 9.8 * 1.6²
s = 12.5 m ←←← Edit: Forgot to say ... that's how high the bridge is above the water
Now get the time it takes the first jumper to reach 1.8 m:
s = v(i)t + (1/2)at²
1.8 = 0 + 4.9t²
t = 0.61 s
so when the 2nd person jumps it takes the first person another 1.6 - 0.61 = 0.99 s to reach the water
Now find how far the 2nd jumper falls in 0.99 s:
s = 0 + 4.9 * 0.99²
s = 4.8 m
so the separation distance between the two jumpers when the 1st jumper hits the water is 12.5 - 4.8 = 7.7 m
Answer: option d.
Explanation:1) The
direction of the
field lines inform about the
sign of the charges.
The field lines <span>
extend from the positive charges to the negative charges, so you can conclude that the charge C is positve and both charge A and charge B are negative:
</span><span>
</span><span>
</span><span>Charge C: positive
</span><span>
</span><span>Charge A: negative
</span><span>
</span><span>Charge B: netative
</span>
2) The
density of the lines (number of lines in a region) inform about the
magnitude of the electric field.
Since the charges are at the same distance, the magnitude of the electric field informs directly about the magnitude of the force and that about the magnitude of the charges.
Since, there are the
double of lines between C and B than between C and A, the magnitude of
charge B is the double than the magnitud of charge A.
From the five options given (a throug e) the only that is consistent with that charges A and B have the same sign, that charge C has different sign, and that charge B is the double of charge A is: