When a force of 20.0N is applied to a spring, it elongates 0.20m. Determine the period of oscillation of a 4.0kg object suspende
1 answer:
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Answer:
The time taken for the race is 17.20 s.
Explanation:
It is given in the problem that a 62.0 kg sprinter starts a race with an acceleration of 1.44 meter per second square.The initial speed of the sprinter is zero as it starts from the rest.
Calculate the final speed of the sprinter.
The expression for the equation of the motion is as follows;
Here, u is the initial speed, v is the final speed, a is the acceleration and s is the distance.
Put u= 0, s=30 m and .
Calculate time taken to cover 30 m distance.
The expression for the equation of motion is as follows;
Put u= 0, s=30 m and .
t=6.45 s
Calculate the time taken to complete his race.
T= t+t'
Here, t is the time taken to cover 30 m distance and t' is the time taken to cover 100 m distance.
Put s= 30 m, and s'= 100 m.
T= 17.20 s
Therefore, the time taken for the race is 17.20 s.
Answer: Option (c) is correct answer.
Explanation:
The given reaction equation is as follows.
The number of atoms on reactant side are as follows.
- Fe = 2
- O = 3
- H = 1
- Cl = 1
The number of atoms on product side are as follows.
- Fe = 1
- O = 1
- H = 2
- Cl = 3
Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.
Since number of Fe atoms in reactant side is 2, therefore, multiply by 2 in the product side.
Number of O atoms in reactant side is 3, therefore, multiply by 3 in the product side.
Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.
The number of chlorine atoms on both reactant and product side equals 6.
Thus, the equation will become as follows.
Hence, the equation is balanced.