Answer: (-7,-5)
Step-by-step explanation:
Because when you mark point M and A if you mirror point M and A on the x Axis then you will get (-7,-5)
Answer:
Step-by-step explanation:
Factoring an expression is the process of undoing the multiplication.
Assume you have a function f(x):
![f(x)=x^2+2x-48](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B2x-48)
This can be factored:
![f(x)=(x+8)(x-6)](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B8%29%28x-6%29)
Using multiplication and the distributive property, you arrive back to:
![f(x)=x^2+2x-48](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B2x-48)
Then you can see clearly that all we've done is reverse the multiplication.
Answer:
(-3,-3)
Step-by-step explanation:
If we reflect P (0,0) across x=-3 and then across y=-3, then the new point of P would be (0-3,0-3)=(-3,-3)
Answer:
A).3222
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are from Latvia, or they are not. We are choosing students without replacement. However, since the sample size is large, we can use the binomial distribution to approximate the hypergeometric distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
480 students, of which 96 are from Latvia:
This means that ![p = \frac{96}{480} = 0.2](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B96%7D%7B480%7D%20%3D%200.2)
Sample of 10 students:
This means that ![n = 10](https://tex.z-dn.net/?f=n%20%3D%2010)
Probability that the sample contains at least three Latvian students.
Either there are less than three students from Latvia, or there are at least three. The sum of the probabilities of these events is 1. So
![P(X < 3) + P(X \geq 3) = 1](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%2B%20P%28X%20%5Cgeq%203%29%20%3D%201)
We want
, in which:
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29)
So
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B10%2C0%7D.%280.2%29%5E%7B0%7D.%280.8%29%5E%7B10%7D%20%3D%200.1074)
![P(X = 1) = C_{10,1}.(0.2)^{1}.(0.8)^{9} = 0.2684](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B10%2C1%7D.%280.2%29%5E%7B1%7D.%280.8%29%5E%7B9%7D%20%3D%200.2684)
![P(X = 2) = C_{10,2}.(0.2)^{2}.(0.8)^{8} = 0.3020](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B10%2C2%7D.%280.2%29%5E%7B2%7D.%280.8%29%5E%7B8%7D%20%3D%200.3020)
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1074 + 0.2648 + 0.3020 = 0.6742](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29%20%3D%200.1074%20%2B%200.2648%20%2B%200.3020%20%3D%200.6742)
So
![P(X \geq 3) = 1 - P(X < 3) = 1 - 0.6742 = 0.3258](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%203%29%20%3D%201%20-%20P%28X%20%3C%203%29%20%3D%201%20-%200.6742%20%3D%200.3258)
The closest option is A.
14*4= 56
so 56 would be the answer