Question

3) In the reaction below, how many grams of carbon dioxide are produced when iron III

Answer 1

Answer:

132.03 g

Explanation:

We are given;

• The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

• Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
• Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

Step 1: Calculate the number of moles of CO

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

Step 2: Calculate the number of moles of CO₂

• From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂

• Therefore; the mole ratio of CO to CO₂ is 1 : 1
• Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

                                = 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g