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Liula [17]
3 years ago
6

3) In the reaction below, how many grams of carbon dioxide are produced when iron III

Chemistry
1 answer:
Yanka [14]3 years ago
3 0
<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
  • Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>
  • From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
  • Therefore; the mole ratio of CO to CO₂ is 1 : 1
  • Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

                                = 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g

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There are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molecular mass.

However, given that the number of molecules in calcium hydroxide is 4.07 x 10¹⁵molecules, we need to calculate the number of moles in Ca(OH)2 as follows:

no. of moles of Ca(OH)2 = 4.07 x 10¹⁵ ÷ 6.02 × 10²³

no. of moles = 0.676 × 10-⁸

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Mass of Ca(OH)2 = 74.093 × 6.76 × 10-⁹ moles

Mass = 5.01 × 10-⁷grams.

Therefore, there are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.

Learn more about how to calculate mass at: brainly.com/question/8101390?referrer=searchResults

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