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Lyrx [107]
2 years ago
15

HELP PLS! I NEED TO GET THIS RIGHT! Curious Carl and his lab partner were conducting a variety of experiments to produce gases:

hydrogen, oxygen, and carbon dioxide. In one experiment, they added a piece of magnesium ribbon to 10 milliliters of hydrochloric acid. They observed bubbles being produced and did a variety of tests to identify the escaping gas; it proved to be hydrogen The reaction is represented by the following equation:
Mg + 2HCL -> MgCL2 + H2(g)

Assuming STP, how many moles of hydrogen gas did Carl and his partner collect if they collected 5.6L?
Chemistry
1 answer:
katen-ka-za [31]2 years ago
8 0

Answer:

0.25 mole of H₂

Explanation:

The equation for the reaction is given below:

Mg + 2HCl —> MgCl₂ + H₂

From the question given above, we were told that the reaction produced 5.6 L of H₂.

Thus, we can obtain obtain the number of mole of H₂ that occupied 5.6 L at STP as follow:

1 mole of H₂ occupied 22.4 L at STP.

Therefore, Xmol of H₂ will occupy 5.6 L at STP i.e

Xmol of H₂ = 5.6 / 22.4

Xmol of H₂ = 0.25 mole

Therefore, 0.25 mole of H₂ were obtained from the reaction.

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C

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2 years ago
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If a falling rock undergoes a Δv of 112ms due to an a¯¯¯ of 9.8 m/s2, how long did it fall? A. 6.7 seconds B. 11.4 seconds C. 0.
tresset_1 [31]

Answer:

9.8

Explanation:

5 0
3 years ago
Calculate the pressure of the CO₂ (g) in the container at 425 K.
Elanso [62]

The pressure of the CO₂ = 0.995 atm

<h3>Further explanation</h3>

The complete question

<em>A student is doing experiments with CO2(g). Originally, a sample of gas is in a rigid container at 299K and 0.70 atm. The student increases the temperature of the CO2(g) in the container to 425K.</em>

<em>Calculate the pressure of the CO₂ (g) in the container at 425 K.</em>

<em />

<em />

Gay Lussac's Law

When the volume is not changed, the gas pressure is proportional to its absolute temperature

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

P₁=0.7 atm

T₁=299 K

T₂=425 K

\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{0.7\times 425}{299}=0.995 `atm

<em />

6 0
3 years ago
NO LINKS⚠️
Vesna [10]
From Q = mcΔΤ, the specific heat capacity, c, of the metal that was cooled is c = Q/mΔT = (-769 J)/(46.4 g)(30.0 °C - 101.0 °C) = 0.233 J/g °C. From the table, it appears that this is the specific heat capacity of silver. So, the metal is most like silver.

Note: The value for Q was written as a negative value in the equation as heat energy was given off by the metal when the metal was cooled (from the metal’s point of view, it’s losing heat energy).
4 0
3 years ago
The second-order diffraction for a gold crystal is at an angle of 22.20o for X-rays of 154 pm. What is the spacing between the c
Alenkinab [10]

<u>Answer:</u> The spacing between the crystal planes is 4.07\times 10^{-10}m

<u>Explanation:</u>

To calculate the spacing between the crystal planes, we use the equation given by Bragg, which is:

n\lambda =2d\sin \theta

where,

n = order of diffraction = 2

\lambda = wavelength of the light = 154pm=1.54\times 10^{-10}m     (Conversion factor:  1m=10^{12}pm )

d = spacing between the crystal planes = ?

\theta = angle of diffraction = 22.20°

Putting values in above equation, we get:

2\times 1.54\times 10^{-10}=2d\sin (22.20)\\\\d=\frac{2\times 1.54\times 10^{-10}}{2\times \sin (22.20)}\\\\d=4.07\times 10^{-10}m

Hence, the spacing between the crystal planes is 4.07\times 10^{-10}m

4 0
3 years ago
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