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AlladinOne [14]
2 years ago
8

An object has an initial velocity of 15 m/s. How long must it accelerate at a constant rate of 3. 0 m/s² before its final veloci

ty is equal 30 m/s?.
Physics
1 answer:
Lera25 [3.4K]2 years ago
4 0

Answer: 5 sec

Explanation:

30 = 15 + (3*t)

so, t=(30-15)÷3

       = 5 sec

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Why does time slow down the closer you get to a black hole, I know that time slows down the faster you move through space and th
mylen [45]

Answer:

Near the black hole, The gravitational pull is so strong and the black hole has a lot of stress energy. This causes the clock to tick slower than usual and due to this , Time slows down to a great extent.

3 0
3 years ago
Put the following items in order of the scientific method:Draw conclusions. Ask a question. Develop a theory. Analyze data. Make
const2013 [10]
I think this is the right order.

1.Make an observation
2.Ask a question
3.Develop a hypothesis
4.Experiment or test idea
5.Analyze data
6.Develop a theory
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5 0
3 years ago
A particular circuit toolbox contains only 80 Ω resistors and switches, which can be open or closed. Construct a circuit, fillin
Strike441 [17]

Answer:

Here we need to make parallel connection of two 80 ohm resistors to achieve 40 ohm net resistance.

Explanation:

As we know that the resistances in series add up directly and here we are given with only the resistors of 80 Ω.

So when we connect two resistors of 80 ohm in parallel we get the resultant of 40 ohm.

Mathematically:

\frac{1}{R_p} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{2}{R}

R=80\Omega gives us the only combination of two resistors in parallel.

3 0
3 years ago
⦁ Determining the magnetic flux, A rectangular piece of stiff paper measures 10 cm x 5 cm. You hold the piece of paper in a unif
MArishka [77]

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jguewjdofe

Explanation:

4 0
2 years ago
A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie
Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

Magnetic Field, B = 0.10 T

Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

5 0
3 years ago
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