The speed of an ostrich is measured to be 63 km/h. What is this speed in meters per second?

Physics

1 answer:

Aleksandr [31]2 years ago

3 0

1 km/h = 0,277778 m/s

63 km/h = x

x= (63 × 0,277778)/ 1

x= 17.5

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A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

R1 = 13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

8 0

3 years ago

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A rock is dropped from a bridge to the water below. It takes 2.40 s for the rock to hit the water (a) find the speed in m/s of t

Artyom0805 [142]

Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground

Explanation: Supposing that where not counting air resistance in the equation, the equation $D = ut+\frac{1}{2} at^{2}$ states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.