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bulgar [2K]
3 years ago
10

two porters are available to carry a long timber wood.out of them one is weak.how to do you make less load to the weak one? writ

e with reason.​
Physics
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

Please find the answer in the explanation.

Explanation:

Given that two porters are available to carry a long timber wood.out of them one is weak. how do you make less load to the weak one?

We can make the weak one to carry less load through two different ways or means.

First, if we can locate the centre of gravity and centre of mass of the long timbre wood, the week one can carry the other end away from the center of gravity and centre of mass.

Second, the strong porter can carry the long timbre wood almost to the fulcrum and allow the weak one to support at the other end. By doing this, the weak one will only carry light portion of the load.

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The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.
mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is r_1=1.496\times 10^{11}\ m

The orbital radius of the Mercury is r_2=5.79 \times 10^{10}\ m

The orbital radius of the Pluto is r_3=5.91 \times 10^{12}\ m

We need to find the time required for light to travel from the Sun to each of the  three planets.

(a) For Sun -Earth,

Kepler's third law :

T_1^2=\dfrac{4\pi ^2}{GM}r_1^3

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So,

T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s

(b) For Sun -Mercury,

T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s

(c) For Sun-Pluto,

T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s

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