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3 years ago

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two porters are available to carry a long timber wood.out of them one is weak.how to do you make less load to the weak one? writ

e with reason.

1 answer:

marshall27 [118]3 years ago

4 0

Answer:

Please find the answer in the explanation.

Explanation:

Given that two porters are available to carry a long timber wood.out of them one is weak. how do you make less load to the weak one?

We can make the weak one to carry less load through two different ways or means.

First, if we can locate the centre of gravity and centre of mass of the long timbre wood, the week one can carry the other end away from the center of gravity and centre of mass.

Second, the strong porter can carry the long timbre wood almost to the fulcrum and allow the weak one to support at the other end. By doing this, the weak one will only carry light portion of the load.

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Answer:

156.67 m/s

0.45676 times the speed of sound

Explanation:

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Time taken by the blast waves to reach the ground = $2\ minutes\ 30\ seconds=2\times 60+30=150\ s$

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The velocity of the blast wave is 156.67 m/s

v = Velocity of sound = 343 m/s

$\dfrac{v_b}{v}=\dfrac{156.67}{343}\\\Rightarrow v_b=v\dfrac{156.67}{343}\\\Rightarrow v_b=0.45676v$

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3 years ago

Will give correct answer brainliest

sineoko [7]

$200 \times 80\%$

<h2><em>calculate</em></h2>

<em> $200 \times \frac{80}{100}$ </em>

<h2><em>reduce </em><em>the </em><em>numbers</em></h2>

<em> $2 \times 80$ </em>

<h2><em>multiply</em></h2>

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2 years ago

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Does the voltage of a battery affect the strength of an electromagnet?

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2 years ago

A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial

Nataly_w [17]

Answer:

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Explanation:

A charged moving particle immersed in a region with magnetic field follows a circular trajectory at constant speed (uniform circular motion), since the magnetic forces acts perpendicular to the direction of motion of the particle.

Since the magnetic force acts as centripetal force, we can write:

$qvB=m\frac{v^2}{r}$

where

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m is the mass of the particle

r is the radius of the orbit

Solving the equation for r,

$r=\frac{mv}{qB}$

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$m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg$

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$v_B=2.90\cdot 10^6 m/s$

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