Answer:
(A). The tension in the rope that connects the boxes is 10.50 N.
(B). The value of m is 7 kg.
Explanation:
Given that,
Mass of box B = 5.00 kg
Mass of box A = m
Force = 40.0 N
Direction= 53.1°
Acceleration = 1.50 m/s²
Coefficient of kinetic friction = 0.30
(A). We need to calculate the tension in the rope that connects the boxes
Using balance equation
Put the value into the formula
(B). We need to calculate the value of m
Using formula of tension
Put the value into the formula
Hence, (A). The tension in the rope that connects the boxes is 10.50 N.
(B). The value of m is 7 kg.
Answer:
Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,
v = 2v
..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,
So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
Answer:
The distance is 300 m.
Explanation:
Given that,
Time = 30 s
Speed = 80 m/s
Distance = 1200 m
Speed of smaller plane = 40 m/s
We need to calculate the acceleration
Using equation of motion
Put the value in the equation
We need to calculate the distance
Using equation of motion
Put the value in the equation
Hence, The distance is 300 m.
The answer is c. the degree of wetness of the paper towels.