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Mariana [72]
3 years ago
5

True or False: The megaspore that develops into the megagametophyte leaves the flower when it

Mathematics
1 answer:
Harrizon [31]3 years ago
6 0

Answer: gang in la

Step-by-step explanation:

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This is a payslip of Mr. Dube a48 years old male employee of a major clothing company​
DiKsa [7]

Answer:

where's the payslip dear

8 0
3 years ago
Which equation shows 6(x + 4) = 2( y + 5) solved for y? A. y = x + 3 B. y = 3x + 5 C. y = 3x + 7 D. y = 3x + 17
UNO [17]

Answer:

C

Step-by-step explanation:

Given

6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation

6x + 24 = 2y + 10 ( subtract 10 from both sides )

6x + 14 = 2y ( divide all terms by 2 )

3x + 7 = y, hence

y = 3x + 7 → C

4 0
3 years ago
Find the least common multiple (LCM) for the pair of numbers 6 and 18 ​
Vadim26 [7]

Answer:

the lcm is 6

Step-by-step explanation:

6 divided by 3 is 1

18 divided by 3 is 6

6 becomes 3 and 2

3 0
3 years ago
Read 2 more answers
How do I work this out
Yuri [45]

Answer:

the total number of blocks is 69

Step-by-step explanation:

the way you can find this is by counting all the outside blocks on the closest side (23) and multiplying it by the the width of the blocks on the right side (3)

6 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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