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3 years ago

True or False:

Chemistry

1 answer:

Juli2301 [7.4K]3 years ago

7 0

Answer:

Explanation:

From the work of Krogh in 1918 until the present time, a very wide range of values for oxygen diffusion coefficients has been reported1–5 ranging from 1.1 × 10−4 to 4 × 10−8 cm2 sec−1.

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when positively charged particles were radiated onto a gold atom, most of the particles went straight past. what is most likely

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0.00001011 kilograms is a larger mass than 0.001011 grams. True or False

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How is the stability of a nucleus affected by changing the number of nuclear particles?

Svet_ta [14]

Answer:

Greatly affected.

Explanation:

The stability of a nucleus is greatly affected by changing the number of nuclear particles because changing the number of nuclear particles i.e. neutron or proton will leads to change the element. When we change the number of protons in an atom, we will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive in nature so we can conclude that changing number of nuclear particles impact the stability of nucleus of an atom.

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3 years ago

A sample of tin (Cp = 0. 227 J/gâ€˘Â°C) is placed in a freezer. Its temperature decreases from 15. 0Â°C to â’10. 0Â°C as it rele

pshichka [43]

Taking into account the definition of calorimetry, the mass of the sample is 478.41 grams.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= -543 J because the energy is releases
c= 0.227 $\frac{J}{gC}$
m= ?
ΔT= Tfinal - Tinitial= 10 C - 15 C= -5 C

Replacing:

-543 J= 0.227 $\frac{J}{gC}$ × m× (-5 C)

Solving:

$m=\frac{-543 J}{0.227 \frac{J}{gC}x(-5 C)}$

<u><em>m=478.41 grams</em></u>

In summary, the mass of the sample is 478.41 grams.

Learn more about calorimetry:

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The most well-known biogenic d-elements

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