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3 years ago

6

True or False:

1 answer:

Juli2301 [7.4K]3 years ago

7 0

Answer:

Explanation:

From the work of Krogh in 1918 until the present time, a very wide range of values for oxygen diffusion coefficients has been reported1–5 ranging from 1.1 × 10−4 to 4 × 10−8 cm2 sec−1.

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What is an example of a community protecting Earth's resources? (2 points)

Lerok [7]

D. A town has started a new recycling and composting program

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3 years ago

Choose any metal atom from Group 1A, 2A, or 3A. What charge will it adopt when it ionizes?

Ksenya-84 [330]

Answer:

Positive charge.

Explanation:

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In this case, since elements belonging to groups 1A, 2A and 3A are mostly metals, we infer they have the capacity to lose electrons and therefore they become positively charged.

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3 years ago

A dangerous condition in a nuclear reactor when fuel rods melt is called

Gnesinka [82]

Answer:

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4 years ago

What is the total oxidation state of the fluorine atoms

Arte-miy333 [17]

Answer:

-1

Explanation:

4 0

3 years ago

Consider the chemical equation for the ionization of CH3NH2 in water. Estimate the percent ionization of CH3NH2 in a 0.050 M CH3

anyanavicka [17]

Answer: The percent ionization of $CH_3NH_2$ in a 0.050 M $CH_3NH_2(aq)$ solution is 8.9 %

Explanation:

$CH_3NH_2+H_2O\rightarrow OH^-+CH_3NH_3^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_b=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= concentration = 0.050 M and $\alpha$ = degree of ionisation = ?

$K_b=4.4\times 10^{-4}$

Putting in the values we get:

$4.4\times 10^{-4}=\frac{(0.050\times \alpha)^2}{(0.050-0.050\times \alpha)}$

$(\alpha)=0.089$

percent ionisation = $0.089\times 100=8.9\%$

8 0

3 years ago