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lara31 [8.8K]
3 years ago
6

True or False:

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

Explanation:

From the work of Krogh in 1918 until the present time, a very wide range of values for oxygen diffusion coefficients has been reported1–5 ranging from 1.1 × 10−4 to 4 × 10−8 cm2 sec−1.

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When a hydrogen atom covalently bonds to another atom, how many electrons associated with this hydrogen atom become involved in
STatiana [176]

Explanation:

A covalent bond is defined as the occurrence of a bond due to the sharing of electrons between the combining atoms.

Atomic number of hydrogen atom is 1 and its electronic configuration is 1s^{2}. So, in order to complete its octet it needs to gain or mutually shares one electron.

A covalent bond is generally formed between non-metal atoms.

Thus, we can conclude that hydrogen has only one electron that will be involved in the formation of a covalent bond.

8 0
3 years ago
If 20 grams of N2 react completely with H2 , how many moles of NH3 are produced? Show Work
Maslowich
This is the balanced eq
N2 + 3H2 -> 2NH3
first you need to find mole of N2 by using
mol = mass ÷ molar mass.
mol N2= 20g ÷ (14.01×2)g/mol
=0.7138mol
then look at the coefficient between H2 and NH3.
it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
moles of NH3 = 1.4276 moles
5 0
3 years ago
Describe the importance of Antoine Lavoisier's work with combustion. Include in the answer the title he was given and what he di
Komok [63]

Answer:

Explanation:

it is very important because with out it we will die

8 0
3 years ago
Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The
Maksim231197 [3]

Answer:

           \large\boxed{\large\boxed{24.6kJ}}

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

     Q=m\times C\times \Delta T

  • m = 10.1g
  • C = 4.18g/JºC
  • ΔT = 100ºC - 55ºC = 45ºC

     Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J

<u>2. Energy to change the liquid to steam at 100ºC</u>

      L=\lambda \times n

  • λ = 40.6kJ/mol
  • n = 10.1g / 18.015g/mol = 0.5606mol

      L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J

<u>3. Total energy</u>

       1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ

7 0
3 years ago
Sea floor spreading occurs at a mid-ocean ridge true or false
Elenna [48]

Answer:

False

Explanation:

sea floor spreading is not consistent at all mid ocean ridges.

7 0
3 years ago
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