<h3><u>Answer</u>;</h3>
C3H4O
<h3><u>Explanation;</u></h3>
Empirical formula is the simplest formula of a compound;
Molar mass CO2 = 44.01
Mass of CO2 produced = 2.053 g
Mass of carbon in original sample = 12.01/44.01 × 2.053
= 0.5603g
Molar mass H2O = 18
Mass of H in original sample = 2/18 ×0.5601
= 0.0622 g
Thus; original sample contained 0.5603g C and 0.0622g H. The balance of the sample was O
Mass of O = 0.8715 - (0.5603 + 0.0622) = 0.249g
The mole ratio of C:H:O will be;
Moles C = 0.5603/12 = 0.0467
Moles H = 0.0622
Moles O = 0.249/16 = 0.01556
C:H:O = 0.0467:0.0622:0.01556
Divide through by 0.01556:
C:H:O = 3:4:1
Empirical formula is thus C3H4O
Answer:- Frequency is
.
Solution:- frequency and wavelength are inversely proportional to each other and the equation used is:

where,
is frequency, c is speed of light and
is the wavelength.
Speed of light is
.
We need to convert the wavelength from nm to m.
(
)

= 
Now, let's plug in the values in the equation to calculate the frequency:

=
or 
since, 
So, the frequency of the green light photon is
.
D. Liquid particles are attracted to each other
For the molarity and the percentage of the mass of kcl are mathematically given as
%m/m = 23.1%, molarity = 3.38M
<h3>What is the molarity?</h3>
Generally, the equation for the percentage of the mass of kcl is mathematically given as
(mass of kcl/mass of solution)x 100
therefore
%m/m = (6.31/27.29)x100
%m/m = 23.1%
The molarity
(no of mol/ vol of sol)
molarity = 0.0846mol/0.0250 L
molarity = 3.38M
In conclusion, the molarity is given as
molarity = 3.38M
Read more about Molarity
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