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3 years ago

Please help Newton second law of motion is F =ma

Physics

2 answers:

mamaluj [8]3 years ago

6 0

Answer: ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

NikAS [45]3 years ago

6 0

Hi there!

Using Newton's Second Law:
$F = ma$

F = Net Force (60 N)
m = mass (30 kg)
a = acceleration (m/s²)

Solve for acceleration given the other values.

$60 = 30a\\\\a = \frac{60}{30} = \boxed{2 \frac{m}{s^2}}$

If the net force increases (while the mass is held constant), the acceleration will INCREASE.

If the mass of the object increases (while the net force is held constant), then the acceleration will DECREASE.

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3 years ago

Correct your friend that says, "The dragster rounded the curve at a constant velocity of 100 km/h." In other words, what is wron

Ainat [17]

Answer:

Correct statement will be dragster rounded the curve with constant speed

Explanation:

It is given that his fried says that The dragster rounded the curve with a constant velocity of 100 km/hour

It is a wrong statement because in circular motion velocity will never constant as the direction of speed is always changing

The correct statement will be dragster rounded the curve with a constant speed because speed may be constant in circular motion

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3 years ago

Bonus: What is the velocity of an 8 kg lead shot-put if it has 484 J of energy? Type here to search e

Dima020 [189]

Answer:

11m/s

Explanation:

Given parameters:

Mass of the lead shot = 8kg

Energy of the shot = 484J

Unknown:

Velocity of the shot = ?

Solution:

To solve this problem, we apply the kinetic energy formula;

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the unknown

Now, insert the parameters and solve;

484 = $\frac{1}{2}$ x 8 x v²

484 = 4v²

v² = 121

v = 11m/s

7 0

3 years ago

A 70.0-kg person throws a 0.0420-kg snowball forward with a ground speed of 35.0 m/s. A second person, with a mass of 57.0 kg, c

ollegr [7]

Answer:

so throwers new velocity = 2.18032m/s

so catchers new velocity = 0.02577m/s

Explanation:

Directly by conservation of momentum we can write

$m_1u_1+m_2u_2= m_1v_1+m_2v_2$

let x be the thrower's new velocity

(70+0.042)×2.2 + 57×0 = 70× x +0.042×35 +57×0

x = 2.18032m/s

so the velocity of 70 kg man = 2.18032m/s

so throwers new velocity = 2.18032m/s

now again by conservation of momentum

0.042×35 = (57+0.042) ×y

y = 0.02577m/s

so catchers new velocity = 0.02577m/s

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3 years ago

A motor has a rating power of 20 W and motor is used for 10 s. Calculate the

zepelin [54]

Explanation:

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6 0

4 years ago

Please help Newton second law of motion is F =ma ​

Please help Newton second law of motion is F =ma