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grandymaker [24]
4 years ago
8

The two figures above are congruent. Find the measure of the angle that isn't labeled on either figure.

Mathematics
1 answer:
harkovskaia [24]4 years ago
7 0

Answer:Idk sry

Step-by-step explanation:

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The base of a right triangle is 13 less than 2 times the height. The area of the triangle is 12 square cm. What is the height of
Romashka [77]

Answer:

The height of the triangle is 8 cm

Step-by-step explanation:

First we need to write down the question in a mathematical format and then solve.

let b be the base of the triangle and h be the height of the triangle

"The base of a right triangle is 13 less than 2 times the height" can be written as

b = 2h - 13 -----------------------------------------------------(1)

"The area of the triangle is 12 square cm" can be written as;

area of the triangle = 12 cm²

but area of a triangle = \frac{1}{2} ×b × h

This implies that

\frac{1}{2} ×b × h = 12 cm²

bh = 24 cm² --------------------------------------------------(2)

substitute equation (1) in equation (2)

(2h - 13)h = 24

2h² - 13h = 24

2h² - 13h - 24 = 0 ----------------------------------------------(3)

The above is now a quadratic equation, so we will solve by completing the square method.

Find two numbers such that its product will give -48 and its sum will give -13

The two numbers are -16 and 3

Replace -13h by  (-16h +  3h) in equation (3)

2h² - 13h - 24 = 0

2h² - 16h + 3h - 24 = 0

2h(h - 8) + 3(h-8) = 0

(h-8)(2h+3) = 0

either h-8 = 0

           h = 8

OR

2h + 3 = 0

2h = -3

h =-3/8

There is no such thing as negative length, therefore h= 8 is the answer

The height of the triangle is 8 cm

3 0
3 years ago
The area of a square battlefield was 22,500 square miles. How long will it take a group of soldiers to cross the field diagonall
VARVARA [1.3K]
\sqrt{22500} = s
\\\ diagonal = s \sqrt{2}
\\\ s = 150, \ diagonal = 150\sqrt{2}
\\\ diagonal \approx 212.132
\\\ 212.132/3.2 \approx 66.291 \ hrs
6 0
3 years ago
Write the number that matches the clues
almond37 [142]
290.

We know that the hundreds is two already.
The tens digit is 9 more than the ones digit, but since a digit can't be more than 9, the ones must be 0.

So the tens is 9 and the ones place is 0. Hopes this helps :)
8 0
3 years ago
A two digits number is 21 times the difference and 350% of the product of its digit. Find the quotient of the digit of number​
Juliette [100K]
The number is 63, so the quotient is 2.

Two digit numbers divisible by 21:
21, 42, 63, 84

21: 2-1 = 1 * 3.5 = 3.5
3.5*2*1 = 7 but 7 does not equal 21

42: 4-2 = 2 * 3.5 = 7
3.5*4*2 = 28 does not equal 42

63: 6-3 = 3*3.5 = 13.5
3.5*6*3 = 63 :)

Check:
21(6-3)=21(3)= 63 :)
3.5(6)(3) = 21(3) = 63 :)

63: 6/3 = 2
3 0
3 years ago
Suppose that the bacteria in a colony grow unchecked according to the Law of Exponential Change. The colony starts with 1 bacter
inn [45]

Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.

Step-by-step explanation:

Since we have given that

Number of bacteria initially = 1

It triples in number every 20 minutes.

So, \dfrac{20}{60}=\dfrac{1}{3}

So, our equation becomes

y=y_0e^{\frac{1}{3}k}\\\\3=1e^{\frac{1}{3}k}\\\\\ln 3=\dfrac{1}{3}k\\\\k=\dfrac{1.099}{0.333}=3.3

We need to find the number of bacteria that it will contain at the end of 24 hours.

So, it becomes,

y=1e^{24\times 3.3}\\\\y=e^{79.1}\\\\y=2.25\times 10^{34}

Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.

3 0
3 years ago
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