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cestrela7 [59]
3 years ago
11

To take a taxi, it costs \$3.00 plus an additional \$2.00per mile traveled. You spent exactly \$20 on a taxi, which includes the

\$1 tip you left. How many miles did you travel
Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0
 A taxi ride where the total fare is $3, $2 for every mile travelled plus a $1 tip and the original cost of $20.

First write a formula that expresses the cost of the ride:

Total cost= Flat fee + Mileage + Tip

Now let's drop in what we know:

20= 3+2 (miles) +1 - we know the total cost is 20, the fee of 3, the tip of 1 and the cost per mile of 2. The only thing we don't know is the number of miles. So let's solve for that.

Subtract 3 and 1 from both sides to get:

16=2(miles)

Divide both sides by 2:

8=miles
Therefore, you traveled 8 miles.
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Jeremy find the cost by adding the percents. 25% off of $60 is equal to 15% off of $60, then subtracting 10% from that cost is e
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Answer:

a. 25% off of $60 is equal to $45.

b. 15% off of $60, then subtracting 10% from that cost is equal to $45.

c. The two total costs are $45 and $45, and their addition is equal to $90 (i.e. $45 + $45 = $90).

Step-by-step explanation:

These can be determined as follows:

a. Calculation of the first total cost, i.e. 25% off of $60

25% of 60 = 25% * $60 = 15

First total cost = 25% off of $60 = $60 - (25% of $60) = $60 - $15 = $45

Therefore, 25% off of $60 is equal to $45.

b. Calculation of the second total cost, i.e. 15% off of $60, then subtracting 10% from that cost

15% of $60 = $9

10% of $60 = $6

Cost = 15% off of $60 = $60 - (15% of $60) = $60 - $9 = $51

Second total cost = Cost - (10% of $60) = $51 - $6 = $45

Therefore, 15% off of $60, then subtracting 10% from that cost is equal to $45.

c. The two total costs

The two total costs are 25% off of $60 which is equal to $45 and 15% off of $60, then subtracting 10% from that cost which is also equal to $45. The addition of the two costs is $90 (i.e. $45 + $45 = $90).

Therefore, the two total costs are $45 and $45, and their addition is equal to $90 (i.e. $45 + $45 = $90).

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Any 10th grader solve it <br>for 50 points​
kkurt [141]

Answer:

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., a_{1}=A and common difference=D

The nth term can be written as

a_{n}=A+(n-1)D

pth term of given arithmetic progression is a

a_{p}=A+(p-1)D=a

qth term of given arithmetic progression is b

a_{q}=A+(q-1)D=b and

rth term of given arithmetic progression is c

a_{r}=A+(r-1)D=c

We have to prove that

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0

Now to prove LHS=RHS

Now take LHS

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)

=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)

=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)

=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}

=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}

=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

\neq 0

ie., RHS\neq 0

Therefore LHS\neq RHS

ie.,\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  

Hence proved

5 0
3 years ago
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