Any change in speed or direction of motion is acceleration.
Constant acceleration can mean ...
-- speeding up at a constant rate . . . gaining the same amount
of speed each second.
-- slowing down at a constant rate . . . losing the same amount
of speed each second.
-- changing direction at a constant rate . . . for example, going
around a circular path at a constant speed.
Answer:
a) T = 608.22 N
b) T = 608.22 N
c) T = 682.62 N
d) T = 533.82 N
Explanation:
Given that the mass of gymnast is m = 62.0 kg
Acceleration due to gravity is g = 9.81 m/s²
Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.
So;
To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;
T = mg
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs the rope at a constant rate tension in the string is
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs up the rope with an upward acceleration of magnitude
a = 1.2 m/s²
the tension in the string is T - mg = ma (Since acceleration a is upwards)
T = ma + mg
= m (a + g )
= (62.0 kg)(9.81 m/s² + 1.2 m/s²)
= (62.0 kg) (11.01 m/s²)
= 682.62 N
When the gymnast climbs up the rope with an downward acceleration of magnitude
a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)
T = mg - ma
= m (g - a )
= (62.0 kg)(9.81 m/s² - 1.2 m/s²)
= (62.0 kg)(8.61 m/s²)
= 533.82 N
Answer:
<h2>1.10 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>1.10 m/s²</h3>
Hope this helps you
Answer:
maximum height: p(t) = Vo * t - 1/2 * g * t^2
p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g
p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2
Vo = 10 m / s. Let’s approximate g = 10 m / s^2
p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)
Calculation of time:
v = u + gt
0 = 10√2 + (-10)t
-10√2 = -10t
2 = √2s
