1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ann [662]
3 years ago
12

As pitch gets higher, wavelength gets?

Physics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

shorter

Explanation:

Margaret [11]3 years ago
4 0
Wavelength gets shorter
You might be interested in
A charge q is at the point x = 5.0 m , y = 0. Write expressions for the unit vectors you would use in Coulomb's law if you were
Flauer [41]

Answer:

A) \^r = \^y

B) \^r = -\^x

C) \^r = -0.14\^x + 0.99\^y

Explanation:

Coulomb's Law is

\vec{F}_{ab} = K\frac{q_1q_2}{r^2}\^r

where r is the distance between the two point charges.

The question clearly asks the unit vector expressions of the force that q exerts on the other charge. So, we do not need to find the force, but only the distance vector, r, between charges, and then we can derive the unit vector pointing only the direction of the force.

A) \vec{r} = \vec{r}_b - \vec{r}_a = (5\^x + \^y) - (5\^x + 0) = \^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{\^y}{1} = \^y

B) \vec{r} = \vec{r}_b - \vec{r}_a = (0 + 0) - (5\^x + 0) = -5\^x\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-5\^x}{5} = -\^x

C) \vec{r} = \vec{r}_b - \vec{r}_a = (4.5\^x + 3.5\^y) - (5\^x + 0) = -0.5\^x + 3.5\^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-0.5\^x + 3.5\^y}{\sqrt{(0.5)^2+(3.5)^2}} = \frac{-0.5\^x + 3.5\^y}{3.53} = -0.14\^x + 0.99\^y

7 0
3 years ago
Read 2 more answers
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the end
yawa3891 [41]

Correct question:

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

a. from the bottom of a hill to the top

b. on a circular nature trail

c. on a sidewalk from his house to the mall

d. from the beginning of a straight track to the end

Answer:

b. on a circular nature trail

Explanation:

As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.

7 0
3 years ago
Read 2 more answers
A snowstorm was predicted in Chicago. Identify the possible upper air temperature, surface temperature, and air pressure of Chic
OverLord2011 [107]
The correct answer for this question is this one:

<span>A snowstorm was predicted in Chicago. The possible upper air temperature, surface temperature, and air pressure of Chicago on that day. Normal atmospheric pressure is 29.9 inches of mercury.  </span><em>I'm pretty sure the answer is 40 for upper air, 29 for surface temp, and 30 for air pressure. </em>Hope this helps answer your question and have a nice day ahead.

7 0
3 years ago
Read 2 more answers
1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential
cupoosta [38]
<h3>Answer:</h3>

\displaystyle U_s = 0.6 \ J

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Physics</u>

<u>Energy</u>

Elastic Potential Energy: \displaystyle U_s = \frac{1}{2} k \triangle x^2

  • U is energy (in J)
  • k is spring constant (in N/m)
  • Δx is displacement from equilibrium (in m)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

k  = 7.50 N/m

Δx = 0.40 m

<u>Step 2: Find Potential Energy</u>

  1. Substitute in variables [Elastic Potential Energy]:                                        \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2
  2. Evaluate exponents:                                                                                      \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)
  3. Multiply:                                                                                                           \displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)
  4. Multiply:                                                                                                           \displaystyle U_s = 0.6 \ J
6 0
3 years ago
A train is moving with a velocity of 70 km/h.
hodyreva [135]

Answer:

B: It is moving north.

Explanation:

We are told that a train is moving with a velocity of 70 km/h.

Now, we are also told that the positive direction is north.

This means that the train is moving in the northern direction.

We can't say if it is speeding up or not because we are not given the acceleration.

Thus, option B is correct

6 0
3 years ago
Other questions:
  • Are Constellations based on the magnitude of stars.
    10·2 answers
  • We can determine the ____________ of a wave when given the frequency and the wavelength.
    14·1 answer
  • How to solve 56 equals 1/2 velocity squared
    15·1 answer
  • A 50kg skater at rest on a frictionless rink throws a 2kg ball, giving the ball a velocity of 10m/s. Which statement describes t
    14·1 answer
  • What is the difference between the control group and the experimental group in an experimental study?​
    15·2 answers
  • Suppose that you and three classmates are discussing the design of a roller coaster. One says that each hill must be lower than
    5·1 answer
  • What will happen to the wave's frequency if its wavelength is made twice as long? A. It will stay the same. B. It will double. C
    10·2 answers
  • A 2-kilogram toy car is traveling forward at 1 meter per second when it is hit in the rear by a 3-kilogram toy truck that was tr
    9·1 answer
  • Best definition of an electromagnetic wave?
    6·1 answer
  • A uniform rod AB is 180Cm long and 2kg. It balances horizontally on a single Support when carrying loads of lkg and 3kg at dista
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!