3 years ago

If an aircraft slows down from 160 km/h to 10 km/h with a uniform of 5 m/s2

Physics

1 answer:

marusya05 [52]3 years ago

8 0

Explanation:

10km/h = 10×10/36=25/9m/sec

160km/h= 160×10/36=400/9

v=a×t

t=v/a

t=(400/9-25/9)/5

t=(125/3)/5=25/3=

$8 \ \frac{1}{3} sec$

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