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lana66690 [7]
3 years ago
6

Vector A⃗ points in the positive y direction and has a magnitude of 12 m. Vector B⃗ has a magnitude of 33 m and points in the ne

gative x direction.
Find the direction of A⃗ + B⃗ .
Find the magnitude of A⃗ + B⃗
Physics
1 answer:
gavmur [86]3 years ago
6 0

vector A has magnitude 12 m and direction +y

so we can say

\vec A = 12 \hat j

vector B has magnitude 33 m and direction - x

\vec B = -33 \hat i

Now the resultant of vector A and B is given as

\vec A + \vec B = 12 \hat j - 33 \hat i

now for direction of the two vectors resultant will be given as

\theta = tan^{-1}\frac{12}{-33}

\theta = 160 degree

so it is inclined at 160 degree counterclockwise from + x axis

magnitude of A and B will be

R = \sqrt{A^2 + B^2}

R = \sqrt{12^2 + 33^2} = 35.11 m

so magnitude will be 35.11 m

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Additional explanation:

(1). The particle separation in a gas is very large because the gas has a very low density, and since particles are not that close together,<em> the strength of forces between particles is very weak</em>.

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