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Nikolay [14]
3 years ago
10

True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6

Physics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

true

Explanation:

Luba_88 [7]3 years ago
3 0

Answer:

true

Explanation:

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Which purpose does a light bulb serve in a circuit?
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Answer:

A light bulb is that component of circuit that lights up when electricity flows through it and vice versa. Its main function is to tell whether electricity is being supplied or not. Its function is also to light up dark places.

Explanation:

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I think its C or D.

Einstein's Nobel winning photoelectric equation.

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Try D

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Does fire use energy??
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Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
1 year ago
If the rifle is stopped by the hunter’s shoulder in a distance of 3.16 cm, what is the magnitude of the average force exerted on
solniwko [45]
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3 years ago
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