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3 years ago

A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground

Physics

2 answers:

GenaCL600 [577]3 years ago

7 0

It will take about 4.2 seconds

Ksivusya [100]3 years ago

7 0

The distance a falling object falls in some amount of time is

D = 1/2 a T²

If this flowerpot falls off a balcony on Earth, then 'a' is the
acceleration of gravity on Earth, and we can write

85 m = 1/2 (9.8 m/s²) T²

Divide each side by 4.9 m/s² :

85/4.9 s² = T²

Square root each side:

T = √(85/4.9) seconds

= 4.165 seconds .

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A computer is reading data from a rotating cd-rom. at a point that is 0.0130 m from the center of the disk, the centripetal acce

likoan [24]

The formula relating acceleration and angular velocity is:

a = ω^2 r

where a is acceleration, ω is angular velocity and r is radius

But the angular velocity ω is constant all throughout the disk therefore:

a1 / r1 = a2 / r2

So at points:

r1 = 0.0130 m -> a1 = 393 m/s^2

r2 = 0.0884 m -> a2 = ?

393 / 0.0130 = a2 / 0.0884

a2 = 2,672.4 m/s^2

6 0

3 years ago

Place a pencil or pen in front of you on the surface that you are working on. In one paragraph, using your own words, describe t

Ede4ka [16]

Answer:

READ THIS FIRST!!!

I am not going to right the parragraph (it says to use your own words, they could trace it back to me if you use my words, and you would get it trouble).

But I will tell you the forces acting on the pencil:

Gravity (pulls on the pencil)

Your hand (pushing it up canceling out gravity)

And the electromagnetic force (holding the thing together)

Hope it helped,

Have a good day

4 0

2 years ago

An experiment is designed to see if sleep affects the number of vocabulary words subjects can remember. The dependent variable i

Kaylis [27]

The dependent variable is: "number of vocabulary words subjects can remember"

<h3>Which is the dependent variable?</h3>

In an experiment, we basically see how changing one variable affects another variable.

In this case, the experiment is:

" if sleep affects the number of vocabulary words subjects can remember."

Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).

So the correct answer is:

"number of vocabulary words subjects can remember"

If you want to learn more about variables:

brainly.com/question/15246027

#SPJ1

7 0

2 years ago

A 1-kilogram mass is attached to a spring whose constant is 21 N/m, and the entire system is then submerged in a liquid that imp

amm1812

Answer:

the required value is $x(t) = \frac{7}{4} e^{-3t}-\frac{3}{4} e^{-7t}$

Explanation:

Given that,

mass, m = 1kg

spring constant k = 21N/M

damping force = $-\beta\frac{dx}{dt} = \frac{-10dx}{dt}$

$\beta = 10$

By Newtons second law ,

The diffrential equation of motion with damping is given by

$m\frac{d^2x}{dt^2} = -kx-\beta\frac{dx}{dt}$

substitute the value of m =1kg, k = 21N/M, and $\beta = 10$

$1\frac{d^2x}{dt^2} = -21x=10\frac{dx}{dt}$

$\frac{d^2x}{dt^2} + 10\frac{dx}{dt} + 21x = 0$

suppose the equation of the form $x =e^m^t$ ,

and the auxilliary equation is given by

$m^2 + 10m + 21 = 0\\\\m^2 + 7m+3m+21=0\\\\m(m+7)+3(m+7)=0\\\\(m+7)(m+3)=0\\\\m=-7\\m=-3$

The general solution for the above differential equation is

$x(t) =C_1e^{-3t}+C_2e^{-7t}$

Derivate with respect to t

$x'(t)=-3C_1e^{-3t}-7C_2e^{-7t}$

(a)

since time is 0 then mass is one meter below

so x(0) = 1

Also it start from rest , that implies , velocity is 0 and time is 0

$x'(0) = 0$

substitute the initial condition

$C_1 +C_2 = 1$

$-3C_1-7C_2=0$

Solve the above equation to get C₁ and C₂

$C_1 =\frac{7}{4} and C_2 = -\frac{3}{4}$

substitute for C₁ and C₂ in general solution

$x(t) = \frac{7}{4} e^{-3t}-\frac{3}{4} e^{-7t}$

Thus the required value is $x(t) = \frac{7}{4} e^{-3t}-\frac{3}{4} e^{-7t}$

3 0

3 years ago

Read 2 more answers

Freight car A with a gross weight of 200,000 lbs is moving along the horizontal track in a switching yard at 4 mi/hr. Freight ca

zhenek [66]

Answer: a) 4.7 mi/hr. b) 86,500 lbs. mi²/Hr²

Explanation:

As in any collision, under the assumption that no external forces exist during the very small collision time, momentum must be conserved.

If the collision is fully inelastic, both masses continue coupled each other as a single mass, with a single speed.

So, we can write the following:

p₁ = p₂ ⇒m₁.v₁ + m₂.v₂ = (m₁ + m₂). vf

Replacing by the values, and solving for vf, we get:

vf = (200,000 lbs. 4 mi/hr + 100,000 lbs. 6 mi/hr) / 300,000 lbs = 4.7 mi/hr

If the track is horizontal, this means that thre is no change in gravitational potential energy, so any loss of energy must be kinetic energy.

Before the collision, the total kinetic energy of the system was the following:

K₁ = 1/2 (m₁.v₁² + m₂.v₂²) = 3,400,000 lbs. mi² / hr²

After the collision, total kinetic energy is as follows:

K₂ = 1/2 ((m₁ + m₂) vf²) = 3,313,500 lbs. mi²/hr²

So we have an Energy loss, equal to the difference between initial kinetic energy and final kinetic energy, as follows:

DE = K₁ - K₂ = 86,500 lbs. mi² / hr²

This loss is due to the impact, and is represented by the work done by friction forces (internal) during the impact.

8 0

3 years ago