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Thepotemich [5.8K]
3 years ago
6

A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground

Physics
2 answers:
GenaCL600 [577]3 years ago
7 0
It will take about 4.2 seconds
Ksivusya [100]3 years ago
7 0
The distance a falling object falls in some amount of time is

        D = 1/2  a  T²

If this flowerpot falls off a balcony on Earth, then 'a' is the
acceleration of gravity on Earth, and we can write

      85 m  =  1/2 (9.8 m/s²) T²

Divide each side by  4.9 m/s² :

      85/4.9  s²  =  T²

Square root each side:

      T  =  √(85/4.9)  seconds

          =      4.165 seconds .
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Answer:

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3 years ago
Which considerations are used to calculate a windchill factor? Select two options.
vlada-n [284]

Wind speed and air temperature are used to calculate a windchill factor.

<u>Explanation:</u>

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Wind-chill factor is the reduction of body temperature due to the passing flow of lower-temperature air.

The air temperature  value is always higher than the wind chill numbers. the heat index will be used if the apparent temperature is higher than the air temperature.So, Wind speed and air temperature are mainly used to calculate a windchill factor.

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3 years ago
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A cup of tea at room temperature of 24°C is heated until it has twice the internal energy. Calculate the final temperature of th
elena-s [515]

The final temperature of the tea cup is 100°C.

<h3>What is internal energy?</h3>

The Internal energy is the energy of a substance due to to the constant random motion of its particles.

The symbol for internal energy of a substance is U and it is measured in Joules.

ΔU = q + W

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  • W is the mechanical work.

In conclusion,  the final temperature of the tea cup at room temperature of 24 °C which is heated until it has twice the internal energy is 100°C.

Learn more about internal energy at: brainly.com/question/24028630

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2 years ago
A mass of 240 grams oscillates on a horizontal frictionless surface at a frequency of 2.5 Hz and with amplitude of 4.5 cm.
mr_godi [17]

Answer:

(a) The spring constant is 59.23 N/m

(b) The total energy involved in the motion is 0.06 J

Explanation:

Given;

mass, m = 240 g = 0.24 kg

frequency, f = 2.5 Hz

amplitude of the oscillation, A = 4.5 cm = 0.045 m

The  angular speed is calculated as;

ω = 2πf

ω = 2 x π x 2.5

ω = 15.71 rad/s

(a) The spring constant is calculated as;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\k = m\omega ^2\\\\where;\\\\k \ is \ the \ spring \ constant\\\\k = (0.24) \times (15.71)^2\\\\k = 59.23 \ N/m

(b) The total energy involved in the motion;

E = ¹/₂kA²

E = (0.5) x (59.23) x (0.045)²

E = 0.06 J

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3 years ago
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TRUE.
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