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3 years ago

Express the following in liters at STP: 6.62 x 10-3 moles HF

Chemistry

1 answer:

serious [3.7K]3 years ago

8 0

Answer:

The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L

Explanation:

Given data:

Number of moles of HF = 6.62×10⁻³ mol

Volume of HF in litter at STP = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Standard temperature = 273 K

Standard pressure = 1 atm

Now we will put the values in formula.

1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K

V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm

V = 148.38×10⁻³ L

Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.

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2 years ago

What is the iupac name of this structure?

alexgriva [62]

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

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3. Identify the substituent group attached to the compound.

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5. Combine the above to name the compound.

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2 years ago

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

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$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

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