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wlad13 [49]
2 years ago
10

Potassium carbonate (K2CO3) has one potassium atom bonded to carbon, and that carbon is also bonded to three oxygens. Their elec

tronegativities are shown in the list:
K 0.82
C 2.55
O 3.44
How would you describe the bonds (K-C and C-O) in this molecule?
A: K-C is polar covalent, and C-O is nonpolar covalent.
B: K-C is ionic, and C-O is nonpolar covalent.
C: K-C is ionic, and C-O is polar covalent.
D: K-C is polar covalent, and C-O is polar covalent.
Chemistry
1 answer:
dybincka [34]2 years ago
3 0

Answer:

I'm not all the way sure but I think it is C

Explanation:

The reason is because an ionic bond essentially donates an electron to the other atom participating in the bond. Also, the C-O I think is polar since it is evenly distributed.

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7 0
3 years ago
A reaction occurs when solid X is placed into solution Y. As a result, the temperature of the new solution increases by 3°C. The
Hoochie [10]

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Explanation:

8 0
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based on the techniqes yo have learned in the organic chemistry lab how would you seperate any unreated alcohol from the ester
mihalych1998 [28]

Answer:

Fractional distillation and HP-LC

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3 0
3 years ago
E the letters of the correct answers on the lines at left.
Neko [114]

Suspension mixture was their dinner if they were having spaghetti and meatballs.  The right option is D.

Explanation:

Properties of suspension mixture are:

Bigger particles are seen in suspension, and they are visible by naked eye.

Suspension is a heterogenous mixture of either two or more substances.

Solute particles are not dissolved in solvent instead they are suspended as it is or in bulk.

Exhibits Tyndall effect.

Solid particles get sedimented easily.

A mixture of spaghetti and meatballs  are suspension because two paricles are not dissoved, and they have separate phases on sphagetti and meat ball where liquid in meat ball drizzles to bottom and meatball remians on top.

3 0
3 years ago
Which substances have /_\Hf = 0 kJ/mol by definition? Select all that apply.
Dimas [21]
Answer: <span>O₂(g), Br₂(l) Fe(s), He(g)
</span>

Justification:

1) The state variable given, ΔHf°, is <span>the standard enthalpy of formation. By definition it is the change in the enthalpy that accompanies the formation of a mole of compound in the standard state, from its constituent elements in the standard state.
</span>

2) Since the standard state of <span>O₂(g), Br₂(l) Fe(s), He(g) is the very same shown, they do not evolve any heat for its formation. This is, that is the same state of the constituents, and no change is involved.
</span>

<span>That is why, </span><span>ΔHf°, of those elements is 0.
</span>
8 0
3 years ago
Read 2 more answers
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