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4 years ago

How many atoms are there in 4.13 moles of nickel (Ni)

Chemistry

1 answer:

Rudik [331]4 years ago

6 0

Answer:

2.48626 x 10^24

Explanation:

We multiple 4.13 by avogadro's number to get that.

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When a cell divides in asexual reproduction what type of cell division is it? *

notka56 [123]

Answer: mitosis

Explanation:

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3 years ago

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During this chemical reaction energy is absorbed. In the chemistry lab, this would be indicated by a decrease in temperature or

Semmy [17]

Reactions like this one absorb energy because the reactants have less potential energy than the products.

<h3>What is an Endothermic reaction?</h3>

This is the type of reaction in which the reactants absorb heat energy from the surroundings to form products.

This brings about a decrease in the temperature as a result of the reactants having less potential energy than the products thereby making option B the most appropriate choice.

Read more about Endothermic reaction here brainly.com/question/6506846

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2 years ago

Form the complementary solution to the homogeneous equation. yc(t) = Cl [ ] +C2 Construct the (simplest) particular olution of t

In-s [12.5K]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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4 years ago

Ammonium hydroxide ionizes as follows: NH4OH(s) NH4 +(aq) + OH-(aq). If an excess of ammonium salt, such as NH4Cl (which ionizes

Flauer [41]

<span>Decrease the concentration of OH-</span>

7 0

3 years ago

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Balance the following redox reaction in basic solution. Cl â’ (aq) + MnO â’ 4 (aq) â†’ Cl 2 (g) + MnO 2 (s)

FinnZ [79.3K]

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) + 4 \; \text{H}_2 \text{O} \; (l) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s) + 8\; \text{OH}^{-} \; (aq)$

<h3>Explanation</h3>

The oxidation state of the manganese atom $\text{Mn}$ changes from +7 as in $\text{MnO}_4^{-}$ to +4 as in $\text{MnO}_2$ .
There are one $\text{Mn}$ atom in each $\text{MnO}_4$ ion.
Reducing each $\text{MnO}_4^{-}$ ion would thus consume three electrons.

Similarly, the oxidation state of the chlorine atom $\text{Cl}$ changes from -1 as in $\text{Cl}^{-}$ to 0 as in $\text{Cl}_2$ .
It takes two $\text{Cl}^{-}$ ions to produce one $\text{Cl}_2$ molecule.
Oxidizing every two $\text{Cl}^{-}$ would thus produce one $\text{Cl}_2$ while releasing two electrons.

Three $\text{Cl}_2$ molecules contain six chlorine atoms. Three $\text{Cl}_2$ would thus correspond to six $\text{Cl}^{-}$ ions.

Combining six $\text{Cl}^{-}$ , two $\text{MnO}_4^{-}$ ions, three $\text{Cl}_2$ ions, and two $\text{MnO}_2$ would balance the changes in oxidation state.

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s)$ (NOT BALANCED)

Still, the product side lacks four oxygen atoms.

In an acidic environment, oxygen atoms would combine with protons to produce water.
In a basic environment (like this one,) there are nearly no protons for oxygen atoms to combine with. Oxygen atoms will likely combine with water to produce hydroxide ions.

Each oxygen atom combine with a water molecule to produce two hydroxide ions. Adding four water molecules and eight hydroxide ions would balance the equation.

5 0

3 years ago