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Mademuasel [1]
2 years ago
9

How do atoms combine to form all of the diverse types of matter in our universe? Pls, Help with a good valid answer and explanat

ion. will mark brainliest.​
Chemistry
1 answer:
german2 years ago
3 0
I don’t understand this
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The compound potassium nitrate is a strong electrolyte. write the reaction when solid potassium nitrate is put into water:
Alenkinab [10]
<span>There is no chemical reaction between potassium nitrate and water. Potassium nitrate dissolves in water, which is a physical change.</span>
7 0
3 years ago
Number 4 Please Help!!!!
Dominik [7]

Answer: c i think

Explanation:

5 0
3 years ago
Ch4+202==&gt;c02+302 what type of chemical reaction
n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

4 0
2 years ago
Can someone help please!
trasher [3.6K]

Answer:

Mixtures

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7 0
3 years ago
Read 2 more answers
How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
3 years ago
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