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Nataly_w [17]
3 years ago
9

Three substances A, B, and C melt at 00C,500C and -1500C

Chemistry
1 answer:
Drupady [299]3 years ago
7 0
Answer:

That information is better presented and analyzed in a table.

This table shows you all the information and the answers:


Substance         melting point   boiling point    room temperature    conclusion
                                    °C                  °C                      °C                    (state)


A                                  0                    100                    25                    liquid

B                                  50                  200                    25                    solid
C                               -150                   10                     25                    gas

Explanation:

1) Substance A at 25° is above the melting point and below the boiling point, then it is liquid (just like water)


2) Substance B at 25°C is below the melting point, so it is solid.

3) Substance C at 25°C is above the boiling point, so it is gas.
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Now we have to calculate the partial pressure of the CO_2 gas.

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\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}

conversion used : (1 Kpa = 0.145 psia)

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